Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
pottersheep
Group Title
I really need help pleaseee.
" Find the dimensions of a rectangle that has a perimeter of 16cm and area of 13 cm^2 "
 2 years ago
 2 years ago
pottersheep Group Title
I really need help pleaseee. " Find the dimensions of a rectangle that has a perimeter of 16cm and area of 13 cm^2 "
 2 years ago
 2 years ago

This Question is Closed

pottersheep Group TitleBest ResponseYou've already chosen the best response.1
anyone ??:(
 2 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
The perimeter of a rectangle can be obtained by the equation \[P = 2(L + W)\] and the area by \[A = LW\] where L and W are different dimensions of the rectangle Do do problems like these, you use one equation to find one dimension in terms of the other, and then substitute that expression into the other equation to find the value of the dimension (and work to find the other dimension as well). I will use the area equation to find the length in terms of width\[L=\frac{13}{W}\] I can substitute that into the equation for the perimeter and then solve for W\[8 = W + \frac{13}{W}\]\[W^28W+13=0\]
 2 years ago

agdgdgdgwngo Group TitleBest ResponseYou've already chosen the best response.3
Using the quadratic formula, I find the positive root (I do not consider the negative root since the dimensions of the rectangle must be positive). I found\[W = \sqrt{3} + 4\] I know that\[L = \frac{13}{W}\]so I just subtitute the value of W in that equation to find \[L = \frac{13}{\sqrt{3}+4}\]
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.1
I LOVE YOU !! I GET IT NOW THANKS SOOO MUCH
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.