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Can someone explain how to do this problem step by step, please

is there any way you could draw it?

The draw function on the site is tough

also what would plug into the t variable, time, to get rid of the t

so you can't draw the figure?

i'll try to draw it...it's going to look brutal though hehe

|dw:1318178380389:dw|

so we have to take the derivative of d=((150-35t)^2+(25t)^2)^(1/2), then plug in 4 for t, right?

Yep

let me know what you get

well I got 1.379, can you show your step on how you got that number

Yeah, expand them first, then take derivative.

You should get:\[\frac{d/dt(150-35t)^2+(25t)^2)}{2\sqrt{(150-35t)^2+(25t)^2)}}\]

wait did you use natural log to expand it?

No. Just expand as usual and you get a polynomial on top. Take the derivative of this polynomial.

is that rule or something because I haven't seen that before except its look similar to natural log

like for example ln x=1/x

The numerator should be:\[d/dt(22500-2(150)(35)t+1225t^2+625t^2)\]

I'm just using the chain rule here

and the normal rule for taking derivatives of roots

gotta go. good luck. hope I earned a medal ;)

lastly did you use (a-b)^(2)=a^2-2ab+b^2 to expand the numerator?

I still didn't get your answer

\[\frac{d/dt(22500-10500t+1225t^2+625t^2)}{2\sqrt{(150-35t)^2+(25t)^2}}\]

This gives:\[\frac{(0-10500+3700t)}{2\sqrt{(150-35t)^2+(25t)^2}}\]

Thanks!

np :)

hey esidl could you help me with one more problem?

sure

ok

its ok, so its suppose dx/dt=squrt(63)/16 on the denominator? Also could you draw a figure again.

no the answer is still dx/dt=sqrt63/8 I just didn't type the 2 in the denominator

2X8=18

oops! I meant 16

|dw:1318192994858:dw|

ok thanks so much

no worries...hope is correct (should be!)

when you take the derivative of inside of square root should be 2x on the denominator

ok, Thanks again