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0001007831

  • 4 years ago

x^3-18x+27

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  1. mwgc
    • 4 years ago
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    (x-3)(x^2+3x-9)

  2. 0001007831
    • 4 years ago
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    what is the divisor

  3. mwgc
    • 4 years ago
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    1

  4. 0001007831
    • 4 years ago
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    can you show me how you worked it out

  5. mwgc
    • 4 years ago
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    the divisor of the coefficients (1,-18,27) is 1

  6. 0001007831
    • 4 years ago
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    what r u dividing it by and will it come out to no remainder

  7. mwgc
    • 4 years ago
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    o so you do want to factor

  8. mwgc
    • 4 years ago
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    then it is x-3/the original equation

  9. mwgc
    • 4 years ago
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    then do long division

  10. 0001007831
    • 4 years ago
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    you r dividing it by 1 but there will be a remainder

  11. mwgc
    • 4 years ago
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    no sry forget the 1 part: at first i thot u wanted me to factor but then when u said divisor i just thot u meant something else

  12. 0001007831
    • 4 years ago
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    soo what r we dividing by then if not 1

  13. mwgc
    • 4 years ago
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    \[(x^{3}-18x+27) \div x-3\]

  14. 0001007831
    • 4 years ago
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    but it will not divide evenly

  15. mwgc
    • 4 years ago
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    to figure out the x-3 part u sub in all factors of 27 til u can make the expression =0

  16. mwgc
    • 4 years ago
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    do long division

  17. 0001007831
    • 4 years ago
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    how do u do it with synthetic division

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