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(x-3)(x^2+3x-9)

what is the divisor

can you show me how you worked it out

the divisor of the coefficients (1,-18,27) is 1

what r u dividing it by and will it come out to no remainder

o so you do want to factor

then it is x-3/the original equation

then do long division

you r dividing it by 1 but there will be a remainder

soo what r we dividing by then if not 1

\[(x^{3}-18x+27) \div x-3\]

but it will not divide evenly

to figure out the x-3 part u sub in all factors of 27 til u can make the expression =0

do long division

how do u do it with synthetic division