## anonymous 4 years ago use Logarthmic Differentiation to solve: y=(sin(3x))^ln(x)

1. anonymous

twig can u go back to my ? about jrotc

2. myininaya

take natural log of both sides $\ln(y)=\ln[(\sin(3x))^{\ln(x)}]$ using properties of log learned in algebra we can write $\ln(y)=\ln(x) \ln(\sin(3x))$ now take derivative of both sides $\frac{y'}{y}=[\ln(x)]'\ln(\sin(3x)]+[\ln(x)][\ln(\sin(3x)]'$

3. myininaya

let me know if you need help with the rest

4. anonymous

HEY JAMES

5. anonymous

Twig are you a girl!!

6. anonymous

myininaya I FINALLY got it thanks to you!!! Thanks a bunch! and bieberfan, yes I am

7. myininaya

np