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twignamanda

  • 3 years ago

use Logarthmic Differentiation to solve: y=(sin(3x))^ln(x)

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  1. bieberfan
    • 3 years ago
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    twig can u go back to my ? about jrotc

  2. myininaya
    • 3 years ago
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    take natural log of both sides \[\ln(y)=\ln[(\sin(3x))^{\ln(x)}]\] using properties of log learned in algebra we can write \[\ln(y)=\ln(x) \ln(\sin(3x))\] now take derivative of both sides \[\frac{y'}{y}=[\ln(x)]'\ln(\sin(3x)]+[\ln(x)][\ln(\sin(3x)]'\]

  3. myininaya
    • 3 years ago
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    let me know if you need help with the rest

  4. bieberfan
    • 3 years ago
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    HEY JAMES

  5. bieberfan
    • 3 years ago
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    Twig are you a girl!!

  6. twignamanda
    • 3 years ago
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    myininaya I FINALLY got it thanks to you!!! Thanks a bunch! and bieberfan, yes I am

  7. myininaya
    • 3 years ago
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    np

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