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Fools101
 4 years ago
Imaginary Numbers
Simplify
i 9
Fools101
 4 years ago
Imaginary Numbers Simplify i 9

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pottersheep
 4 years ago
Best ResponseYou've already chosen the best response.2That is simplified isnt it?

pottersheep
 4 years ago
Best ResponseYou've already chosen the best response.2ah. ok then so 1^2 = 1 right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0simplified version has to be i

Fools101
 4 years ago
Best ResponseYou've already chosen the best response.0Aww idk this kind of confusing me

pottersheep
 4 years ago
Best ResponseYou've already chosen the best response.2(i^2)^4 . i (1)^4 . i 1i

pottersheep
 4 years ago
Best ResponseYou've already chosen the best response.2(i^2)^4 . i (1)^4 . i 1i

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0any variable equals 1 automatically

pottersheep
 4 years ago
Best ResponseYou've already chosen the best response.2Basically take out an i^2 first so that you work with 1. I.e i^4 = (i^2)^2 so now you have (1)^2 = 1. Do you understand up to there?

Fools101
 4 years ago
Best ResponseYou've already chosen the best response.0KIND of so it 1? a little ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if there is no value to a variable it becomes a 1.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[i^9=i^{4 \cdot 2 +1}=i^{4 \cdot 2} \cdot i^1=(i^4)^2 \cdot i=(1)^2 \cdot i\] \[=1 \cdot i=i\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pattern is \[i^0=1\] \[i^1=i\] \[i^2=1\] \[i^3=i\] \[i^4=1\] and so on. so your real job is to take the integer remainder when you divide the power by 4. for example \[i^{103}=i^3=i\]

Fools101
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhh i see !!! kk thank u that make sense !!!
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