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pottersheepBest ResponseYou've already chosen the best response.2
That is simplified isnt it?
 2 years ago

pottersheepBest ResponseYou've already chosen the best response.2
ah. ok then so 1^2 = 1 right
 2 years ago

Blank123Best ResponseYou've already chosen the best response.0
simplified version has to be i
 2 years ago

Fools101Best ResponseYou've already chosen the best response.0
Aww idk this kind of confusing me
 2 years ago

pottersheepBest ResponseYou've already chosen the best response.2
(i^2)^4 . i (1)^4 . i 1i
 2 years ago

pottersheepBest ResponseYou've already chosen the best response.2
(i^2)^4 . i (1)^4 . i 1i
 2 years ago

Blank123Best ResponseYou've already chosen the best response.0
any variable equals 1 automatically
 2 years ago

pottersheepBest ResponseYou've already chosen the best response.2
Basically take out an i^2 first so that you work with 1. I.e i^4 = (i^2)^2 so now you have (1)^2 = 1. Do you understand up to there?
 2 years ago

Fools101Best ResponseYou've already chosen the best response.0
KIND of so it 1? a little ...
 2 years ago

Blank123Best ResponseYou've already chosen the best response.0
if there is no value to a variable it becomes a 1.
 2 years ago

myininayaBest ResponseYou've already chosen the best response.1
\[i^9=i^{4 \cdot 2 +1}=i^{4 \cdot 2} \cdot i^1=(i^4)^2 \cdot i=(1)^2 \cdot i\] \[=1 \cdot i=i\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
pattern is \[i^0=1\] \[i^1=i\] \[i^2=1\] \[i^3=i\] \[i^4=1\] and so on. so your real job is to take the integer remainder when you divide the power by 4. for example \[i^{103}=i^3=i\]
 2 years ago

Fools101Best ResponseYou've already chosen the best response.0
ohhhh i see !!! kk thank u that make sense !!!
 2 years ago
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