## waheguru 4 years ago PLEASE DONT GIVR THE ANSWER JUST TAKE ME STEP BY STEP UNTIL I --- GET THE ANSWER A CIRCULAR GARDEN HAS A DIAMETER OF 12M BY HOW MUCH DOES TEH DIAMETER HAVE 2 BE INCREASED SO THAT THE AREA TRIPLES

1. pottersheep

2. LagrangeSon678

radius is (Diameter)/(2) so for the area to be tripled i guess we can simply triply the radius

3. pottersheep

So area of circle: πr2 Diameter: 12 so Radius :6m The area we have now: π(6)^2 = 113.1m^2 area we need = 113.1m^2 x 3 = 339.2

4. waheguru

yea i got that so far

5. pottersheep

I'm thinking :P

6. waheguru

hmm

7. pottersheep

πr2 = 339.2 r^2 = 339.3/pi

8. waheguru

thats what i was doing jus now =)

9. pottersheep

r^2 = 108 (im rounding the numbers :P) r = 10.4

10. waheguru

YAY I ALSO GOT THAT but the asnwers say 8.8m

11. pottersheep

darn. are you sure you wrote the question right?

12. waheguru

lets plug it in and see if it is tripled

13. waheguru

yea im sure bro

14. pottersheep

OH I GET WHY. Because you have to say how much it increases by

15. waheguru

?

16. pottersheep

Radius now is 10.4 for diameter is 20.8. Before the diameter was 12.

17. pottersheep

*so diameter is 20.8

18. waheguru

and bak 2 our andwer 10.4

19. waheguru

oh never mind

20. pottersheep

whoopdedoo

21. waheguru

whait how dod u get it agiin sry

22. pottersheep

20.8 - 12 =

23. pottersheep

8.8 =D

24. waheguru

YEYYYYYYYYYYYY WE DID IT I GOT IT 2 THX BROOOOOO

25. pottersheep

I'm a girl but no problem=)

26. waheguru

OH sry

27. waheguru

28. pottersheep

29. waheguru

wow im just in grade 9

30. waheguru

where u from

31. pottersheep

32. waheguru

me 2

33. waheguru

hudson bay?

34. pottersheep

Grade 9 math can be kind of confusing since it's the first year of highschool and everyone learned different things from different schools . =)

35. pottersheep

my school's in ontario

36. waheguru

yea thx 4 ur help

37. pottersheep

no problem

38. waheguru

bye

39. pottersheep

byebye lol

40. dmancine

$\frac{A_{2}}{A_{1}}=\frac{\pi r_{2}^{2}}{\pi r_{1}^{2}}$$3=\frac{\pi r_{2}^{2}}{\pi 6^{2}}=\frac{r_{2}^{2}}{36}$etc.