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anonymous
 5 years ago
Suppose f '(2) = 3 and g '(2) = 8
Find h'(2) where h(x) = 5f(x) + 3g(x) +1
h'(2) =
anonymous
 5 years ago
Suppose f '(2) = 3 and g '(2) = 8 Find h'(2) where h(x) = 5f(x) + 3g(x) +1 h'(2) =

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0h'(x) = 5f'(x) +3g'(x) +1 => h'(2) = 5(3) +3(8) +1 =15+24+1 = 40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer to the problem said that it was 39:PP its like an online hw assignment

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know how its 39 though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhhhhhhhhh i'am sorry i made a mistake!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0h'(x) = 5f'(x) +3g'(x) +1 => h'(2) = 5(3) +3(8) =15+24 = 39 (if we differentiate 1 we get 0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh i see haha thank you:)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0h[x] = 5 f[x] + 3 g[x] + 1 h'[2]=5 f ' [2]+3 g'[2] h'[2]=5*3 + 3*8 h'[2]=15 + 24 h'[2]=39

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0myinmi, hello, i think i see why the discrepancy in my problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the problem you have to take the square root of tan^2 theta, but we know that the square root of x^2 is x, and for the theta in the problem we have a negative answer
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