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NatalieLove

  • 4 years ago

Factor completely 121x2 – 88x + 16

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  1. anonymous
    • 4 years ago
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    this one you recognize as a "perfect square" because \[121x^2=(11x)^2, 16=(-4)^2, 2\times 11\times 4=88\] so you get \[(11x-4)^2\]

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