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Write a function named `dayCount()` that accepts a month, day, and year as its input arguments; calcuates an integer representing the total number of days from the turn of the century to the date that's passed; and returns the calculated integer to the calling function. For this problem, assume each year has 365 days and each month has 30 days. You need to write a main function to prompt for year, month and day. You need to validate the input and ask user reenter one if not correct. Note you should use exact function name in your program.

Computer Science
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int dayCount(int day, int month, int year) { total=day + (month *30) + ((year-2000) *365); return total; } For the turn of the century, you need the closest 100, you should use year%100, which will yield the last two digits of the year. If year 1999, it will yield 99. If 2011, it will yield 11.
I just saw your code limits the year to be bigger than 2000, but anyway using the year%100 should yield correct answer to any number larger than 2100. Since the restrictions of the problem do not include the year, I would probably remove the year limitation, probably set it to any non-negative number?
hmmm perhaps you are right. I was confused about the turn of the century dillemma. Let me know it out. Thanks a bunch :D

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Good luck :)
Doesn't work out :( lol. It says, the tests fail on -Test Failed on invalid inputs -Test Failed on y=3985, m=1, d=15 -Test Failed on y=2011, m=10, d=5
Example 1: Enter a correct year (>=0): -5 Enter a correct year (>=0): 2001 Enter a correct month (>=1 and <=12): 15 Enter a correct month (>=1 and <=12): 1 Enter a correct day: -12 Enter a correct day: 36 Enter a correct day: 15 The total days are: 380 Example 2: Enter a correct year (>=0): 3045 Enter a correct month (>=1 and <=12): 1 Enter a correct day: 15 The total days are: 16440 Here are example problems my professor posted :/
What are the outputs for your failed tests?
For d=15, m=1 and year =3985, my output is 31070 :/
Ah, I think I see the mistake. You're multiplying month: 1 as 30 days. At month 1 technically you still haven't gone through 30 days. Try modifying ((month-1) * 30) inside the dayCount() function
Hmmm really? 1 month =30 days though right? or are you saying at month 1, 30 days haven't passed yet?
At month 1, you still haven't gone through 30 days. As in m = 1 d = 15 You're at January 15, therefore you're at day 15, not 45 as your function would now return.
and yeah, it still fails
oh hmmm
This operation returns the correct value: day + (month-1) * 30 + (year%100) * 365; What is checking if your tests succeed or fail, an automatic program where you submit your code?
yeah an automatic program
Yeah I thought it would work but it doesn't work on the program for some reason :( I wonder what i am doing wrong...
Normally, automatic programs check output down to the last space and comma, that is, your program should output EXACTLY as shown in the example. do { cout <<"Enter a correct year: "; cin >> year; } while(year<0); should be do { cout <<"Enter a correct year (>= 0): "; cin >> year; } while(year<0); and so on.
It shouldn't and it doesn't change anything because you can write anything in the cout string but idk... Thanks for the help anyway :D I appreciate it :D
The times I've struggled with automatic checkers have been with a randomly inserted space I missed, double check just to make sure. What do you mean you can write anything in the cout String, whoever is running the application can't actually modify cout at runtime can they? (Don't know much about C#)
Oh no they can't. I meant to say cout <<"Enter a num: " << num << endl; and cout << "Num: " << num << endl; give you the same output regardless (taking your last post as an example)...Idk what could be wrong though and yeah checkers are annoying a bit in that regard.
Can you take a look at my other question too if you have the time? I just want feedback. Thanks a bunch!!! :D
i did something like this in C a while ago...
heres the function http://ideone.com/sw3ux
mine does something diffferent tho :-P

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