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you cant negate an absolute value
\[|something| \neq negative something \]
| | = -# not good
sites still going slow
so what happens when you subtract 16 on both sides don't we have |junk|=negative something?
|x+2| +16=14 -16 -16 |x+2|=-2 x+2=-2 -2 -2 x=-4 I don't know how you got the second part but that's how i would do the first part
|x+2|=-2 never happens for any input
|something| is either positive or neutral
|something| is never negative
What do you mean? you just drop you absolute value and subtract 2 on both sides to cancel out the 2 on the side with the variable. and only |inside| has to positive..everything outside the | | can be whatever
we can put anything into | | and the output will either be 0 or positive
| | represents distance
distance is either positive or zero
distance is never negative
| | is called absolute value.. look it up on google.. Are you talking about highschool algebra or college?
absolute value is the distance of some number to 0
|-3|=3 |0|=0 |3|=3 |-141441|=141441 look the outputs are never negative
So the answer is no solution ?
That's what i'm saying.. I didn't put a negative inside the bars i put them on the outside
butter ask yourself can you ever get a negative output for |something| the answer is no
|junk| is never negative
\[|junk| \neq negative something \]
I know that... i didn't make |junk| negative it was still positive
I know that an absolute value can never be negative!
then what you know there is no solution
to this equation you have
Okay, thank you. Just making sure.
\[|x+2| \neq -2 \]
see there is no negative except on the OTHERSIDE of the = sign.. and you can do that..
no you cannot |junk| is never negative
|x+2|=-2 has no solution
|x+2| is positive or neutral -2 is always negative how could they ever be the same?
they are not the same... that's not a finished equation
|x+2| will never be the same as -2 for any x
\[|x-a|\] is the distance from x to a. for example \[|5-8|=3\] because the distance between 5 and 8 is 3. as such, it cannot be negative. so if you ever see \[|x-a|=-3\] for example, go get a snack and forget about trying to solve it. there is no solution to such a thing
I don't understand. but okay.
= means the same...
yes = means we are looking for when two expressions are the same or meet or intersect
therefore |something|=something else means that even if the equation isn't finished it is still equal and therefore saying that |something|=negative something is wrong
right |junk| is never negative
you can say |-something|=something or -|something|=negative something or even -|-something|=negative something but you cant say |something|=negative something
or better yet, lets prove if Beccas result is good? |x+2| +16=14 -16 -16 |x+2|=-2 x+2=-2 -2 -2 x=-4 lets assume x=-4 and use it in our equation. |-4+2| +16=14 |-2| +16=14 2+16=14 18=14 .... this is a contradiction; so x cannot = -4
we can go even further and try to work this out like it would pop out a good result: |x + 2| +16 = 14 -16 -16 ---------------- |x+2| = -2 (x+2) = -2 or -(x+2) = -2 -2 -2 -x-2 = -2 +2 +2 -------------------------- x = -4 or -x = 0; or simply x=0 these are the only 2 possible solutions we can get from it; and we already tested x=-4 and it failed us. Lets test out x=0 |0 + 2| +16 = 14 |2| +16 = 14 2 +16 = 14 18 = 14 ... another bad result; since x cannot be the only 2 options that would naturally fit; the answer has to be that nothing will fit.
This is a redimentary proof that: |N| = -# is just plain false