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buttermequeasy
|x + 2| + 16 = 14 x = −32 and x = −4 x = −4 and x = 0 x = 0 and x = 28 No solution
you cant negate an absolute value
\[|something| \neq negative something \]
sites still going slow
so what happens when you subtract 16 on both sides don't we have |junk|=negative something?
|x+2| +16=14 -16 -16 |x+2|=-2 x+2=-2 -2 -2 x=-4 I don't know how you got the second part but that's how i would do the first part
|x+2|=-2 never happens for any input
|something| is either positive or neutral
|something| is never negative
What do you mean? you just drop you absolute value and subtract 2 on both sides to cancel out the 2 on the side with the variable. and only |inside| has to positive..everything outside the | | can be whatever
we can put anything into | | and the output will either be 0 or positive
| | represents distance
distance is either positive or zero
distance is never negative
| | is called absolute value.. look it up on google.. Are you talking about highschool algebra or college?
absolute value is the distance of some number to 0
|-3|=3 |0|=0 |3|=3 |-141441|=141441 look the outputs are never negative
So the answer is no solution ?
That's what i'm saying.. I didn't put a negative inside the bars i put them on the outside
butter ask yourself can you ever get a negative output for |something| the answer is no
|junk| is never negative
\[|junk| \neq negative something \]
I know that... i didn't make |junk| negative it was still positive
I know that an absolute value can never be negative!
then what you know there is no solution
to this equation you have
Okay, thank you. Just making sure.
see there is no negative except on the OTHERSIDE of the = sign.. and you can do that..
no you cannot |junk| is never negative
|x+2|=-2 has no solution
|x+2| is positive or neutral -2 is always negative how could they ever be the same?
they are not the same... that's not a finished equation
|x+2| will never be the same as -2 for any x
\[|x-a|\] is the distance from x to a. for example \[|5-8|=3\] because the distance between 5 and 8 is 3. as such, it cannot be negative. so if you ever see \[|x-a|=-3\] for example, go get a snack and forget about trying to solve it. there is no solution to such a thing
I don't understand. but okay.
yes = means we are looking for when two expressions are the same or meet or intersect
therefore |something|=something else means that even if the equation isn't finished it is still equal and therefore saying that |something|=negative something is wrong
right |junk| is never negative
you can say |-something|=something or -|something|=negative something or even -|-something|=negative something but you cant say |something|=negative something
or better yet, lets prove if Beccas result is good? |x+2| +16=14 -16 -16 |x+2|=-2 x+2=-2 -2 -2 x=-4 lets assume x=-4 and use it in our equation. |-4+2| +16=14 |-2| +16=14 2+16=14 18=14 .... this is a contradiction; so x cannot = -4
we can go even further and try to work this out like it would pop out a good result: |x + 2| +16 = 14 -16 -16 ---------------- |x+2| = -2 (x+2) = -2 or -(x+2) = -2 -2 -2 -x-2 = -2 +2 +2 -------------------------- x = -4 or -x = 0; or simply x=0 these are the only 2 possible solutions we can get from it; and we already tested x=-4 and it failed us. Lets test out x=0 |0 + 2| +16 = 14 |2| +16 = 14 2 +16 = 14 18 = 14 ... another bad result; since x cannot be the only 2 options that would naturally fit; the answer has to be that nothing will fit.
This is a redimentary proof that: |N| = -# is just plain false