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flycherrypie

  • 4 years ago

3s^2-24s+48

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  1. Mandolino
    • 4 years ago
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    given\[3s^2-24s+48\]factor out the common 3\[=3(s^2-8s+16)\]inside the parentheses is similar to your last posting\[=3(x-4)^2\]since -4*-4=16 and -4-4=-8

  2. ndog33
    • 4 years ago
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    3(s^2-8s+16) = 3(s-4)(s-4)

  3. giggles123
    • 4 years ago
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    \[3(s^2-8s+16)--->3(s-4)(s-4)--->\] Then =3(x−4)2 since -4*-4=16 and -4-4=-8

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