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flycherrypie
3s^2-24s+48
given\[3s^2-24s+48\]factor out the common 3\[=3(s^2-8s+16)\]inside the parentheses is similar to your last posting\[=3(x-4)^2\]since -4*-4=16 and -4-4=-8
3(s^2-8s+16) = 3(s-4)(s-4)
\[3(s^2-8s+16)--->3(s-4)(s-4)--->\] Then =3(x−4)2 since -4*-4=16 and -4-4=-8