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becca18Best ResponseYou've already chosen the best response.0
y'[x] == (3 E^y + Derivative[1, 0][f][x, y])/(3 E^y + 3 E^y x + 3 E^y y  Derivative[0, 1][f][x, y])
 2 years ago

ZarkonBest ResponseYou've already chosen the best response.2
\[f_x=3e^y\] \[f_y=(3x+3y)e^y+3e^y\]
 2 years ago

The_G.O.A.TBest ResponseYou've already chosen the best response.0
f'x = 3e^y(3x+3y) f'y = 3e^y(3x+3y)
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
why dn't you just multpply them out... i beleive that zarkon is correct
 2 years ago

The_G.O.A.TBest ResponseYou've already chosen the best response.0
outside inside rule e^y will stay e^y always, leave inside then multiply inside respect to x and y.
 2 years ago

The_G.O.A.TBest ResponseYou've already chosen the best response.0
zarkon is probably right though go with zarkon.
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
if you multiply it out Goat you get 3xe^y+3ye^y fx =3e^y + 0 fy=3xe^y+3e^y=3e^y(x+1)
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
could be errors but i just did that without paper
 2 years ago

ZarkonBest ResponseYou've already chosen the best response.2
use the product rule for fy
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
ahh yes both y's so yeah
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
but the first is correct
 2 years ago

The_G.O.A.TBest ResponseYou've already chosen the best response.0
yep i see thanks i am working on my understanding of this as well.
 2 years ago

barry_chauBest ResponseYou've already chosen the best response.0
so how would I find fxx and fyy
 2 years ago

ZarkonBest ResponseYou've already chosen the best response.2
just take the derivative again
 2 years ago

ZarkonBest ResponseYou've already chosen the best response.2
\[f_{xx}=0\] \[f_{yy}=(3y+3x+6)e^y\]
 2 years ago
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