Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find the partial derivative of f(x,y)=(3x+3y)e^y

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

y'[x] == (-3 E^y + Derivative[1, 0][f][x, y])/(3 E^y + 3 E^y x + 3 E^y y - Derivative[0, 1][f][x, y])
\[f_x=3e^y\] \[f_y=(3x+3y)e^y+3e^y\]
f'x = 3e^y(3x+3y) f'y = 3e^y(3x+3y)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

why dn't you just multpply them out... i beleive that zarkon is correct
i am ;)
outside inside rule e^y will stay e^y always, leave inside then multiply inside respect to x and y.
zarkon is probably right though go with zarkon.
if you multiply it out Goat you get 3xe^y+3ye^y fx =3e^y + 0 fy=3xe^y+3e^y=3e^y(x+1)
could be errors but i just did that without paper
use the product rule for fy
ahh yes both y's so yeah
but the first is correct
yep i see thanks i am working on my understanding of this as well.
so how would I find fxx and fyy
just take the derivative again
\[f_{xx}=0\] \[f_{yy}=(3y+3x+6)e^y\]
and fxy = 3e^y?
thank you!

Not the answer you are looking for?

Search for more explanations.

Ask your own question