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Passes through (3,1) and perpendicular to graph of y=1/2x+3?
Explain. Passes through (3,1) and perpendicular to graph of y=1/2x+3?
Explain. @Mathematics
 2 years ago
 2 years ago
Passes through (3,1) and perpendicular to graph of y=1/2x+3? Explain. Passes through (3,1) and perpendicular to graph of y=1/2x+3? Explain. @Mathematics
 2 years ago
 2 years ago

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Tyler1992Best ResponseYou've already chosen the best response.1
Perpendicular slopes will equal 1 so to find the perpendicular slope of 1/2 you do this \[\frac{1}{2} + x = 1\] Solve for x and you get the perpendicular slope of 2
 2 years ago

Tyler1992Best ResponseYou've already chosen the best response.1
now that you have a point on the graph and a slope, use the point slope formula
 2 years ago

Tyler1992Best ResponseYou've already chosen the best response.1
\[y  1 = 2(x  3)\] solve for y \[y = 2x + 7\]
 2 years ago

becca18Best ResponseYou've already chosen the best response.0
Thanks, I just don't understand this stuff.. My teacher is WACK and won't explain it to me.. Thank you though!
 2 years ago

Tyler1992Best ResponseYou've already chosen the best response.1
Just remember that perpendicular slopes add up to 1.. or the easy way is to do the negative reciprocal. Reciprocal means to flip the fraction and then all you have to do is negate it. So if you have a slope of 3/2 and you want the perpendicular slope all you do is flip the fraction... 2/3.. then negate it.. so the slope perpendicular to 3/2 would be 2/3. Understand??
 2 years ago

becca18Best ResponseYou've already chosen the best response.0
Yeah I think I got it! My teacher just needs to teach it like that! THANKS!
 2 years ago
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