A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

LagrangeSon678
 3 years ago
Best ResponseYou've already chosen the best response.0anybody can help me?

becca18
 3 years ago
Best ResponseYou've already chosen the best response.0What's that supposed to mean?

agreene
 3 years ago
Best ResponseYou've already chosen the best response.0tan(x)sec(x) This are all very common derivatives... your book should have a table of them somewhere... and I would suggest just memorizing all of the trig derivatives and integrals, it will come in handy when you get to trig substitution integration.

Tyler1992
 3 years ago
Best ResponseYou've already chosen the best response.0ok.. sec(x) is the same as \[\frac{1}{\cos(x)}\] So use the quotient rule to find the derivative... \[\frac{\cos(x)(0)  1(\sin(x))}{\cos^2(x)}\] Simplify and you get \[\frac{\sin(x)}{\cos^2(x)}\] This can be written as \[\frac{1}{\cos(x)} * \frac{\sin(x)}{\cos(x)}\] Which is sec(x)tan(x)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.