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neoh147
find the locus of point such that its distance from point (3,-3) is always equal to its distance from the straight line y=x-2 Pls show steps
(a,b) be a point on the locus....................... the line is also x-y-2=0 then (3-a)^2 + (-3-b)^2 = ((a-b-2)^2)/2
sry just nw i went out... left hand side i can understand... but can i know where right hand side come from??
http://mathworld.wolfram.com/Point-LineDistance2-Dimensional.html
point to a line distance
thx.. i think i get it already...