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GOODMAN

  • 3 years ago

BOX AND WHISKER PLOTS!!! BOX AND WHISKER PLOTS!!! @Mathematics

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  1. GOODMAN
    • 3 years ago
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    {1055, 1075, 1095, 1125, 1005, 975, 1125, 1100, 1145, 1025, 1075}

  2. GOODMAN
    • 3 years ago
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    HEY...can show me how to make one for this...and to find the outliers

  3. Zarkon
    • 3 years ago
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    are you using Tukey’s rule?

  4. GOODMAN
    • 3 years ago
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    wat is tukeys rule..LOL

  5. GOODMAN
    • 3 years ago
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    we are using matrices....

  6. Zarkon
    • 3 years ago
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    for finding outliers

  7. Zarkon
    • 3 years ago
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    matrices for a box plot?

  8. GOODMAN
    • 3 years ago
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    dunno...wat is tukeys rule..can u teach me?

  9. Zarkon
    • 3 years ago
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    find the quartiles

  10. GOODMAN
    • 3 years ago
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    not ezactly...tas the chapter were on...technically it has nothing to do with matrices which i find funny...YES QUARTILES..FIND THOSE TOO

  11. Zarkon
    • 3 years ago
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    and the interquartile range

  12. GOODMAN
    • 3 years ago
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    YEA..THAT TOOO!! MAN U READ MY PAPER...

  13. Zarkon
    • 3 years ago
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    compute \[Q_1-1.5IQR\] and \[Q_3+1.5IQR\]

  14. GOODMAN
    • 3 years ago
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    WAT ARE THE QUARTILES?

  15. Zarkon
    • 3 years ago
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    do you know how to find the median?

  16. GOODMAN
    • 3 years ago
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    yea...

  17. Zarkon
    • 3 years ago
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    do that...that is \[Q_2\]

  18. GOODMAN
    • 3 years ago
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    okay...then its 975...

  19. Zarkon
    • 3 years ago
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    then find the median of the lower half of the data...that is \[Q_1\] then find the median of the upper half of the data...that is \[Q_3\]

  20. myininaya
    • 3 years ago
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    |dw:1319592543903:dw| isn't this a box and whisker thingy? also i think i'm missing an element and i keep going over the data again and again so i don't know which one i'm missing :( i think i;m getting old

  21. Zarkon
    • 3 years ago
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    |dw:1319592983243:dw|

  22. GOODMAN
    • 3 years ago
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    q1 is |dw:1319592990892:dw|its sumthing like tat...

  23. GOODMAN
    • 3 years ago
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    wow..mines a fail

  24. Zarkon
    • 3 years ago
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    remember you need to sort the data in order to find the median

  25. GOODMAN
    • 3 years ago
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    oh ya...lolz

  26. myininaya
    • 3 years ago
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    what i made i think is called a stem and leaf thingy ma jigger

  27. Zarkon
    • 3 years ago
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    correct

  28. GOODMAN
    • 3 years ago
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    YEA!!! STEM AND LEAF PLOT!!! lols i hated those

  29. myininaya
    • 3 years ago
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    ok zarkon what element am i missing though i have 10 elements he has 11 i have been over his set over and over and i can't figure out which one i'm missing

  30. GOODMAN
    • 3 years ago
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    whose he?

  31. GOODMAN
    • 3 years ago
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    who has 11 elements?

  32. myininaya
    • 3 years ago
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    you have 11 elements

  33. GOODMAN
    • 3 years ago
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    ohh....lolz im a girl...wow i got confused tare...

  34. myininaya
    • 3 years ago
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    do i know how to count?

  35. Zarkon
    • 3 years ago
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    not sure...but you wouldn't want to write the stem and leaf like that anyway...the stems need to be uniform...yours are not :)

  36. myininaya
    • 3 years ago
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    i like my stem and leaf :(

  37. Zarkon
    • 3 years ago
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    1075

  38. myininaya
    • 3 years ago
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    no i see 1075

  39. Zarkon
    • 3 years ago
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    there are two of them

  40. myininaya
    • 3 years ago
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    oh it occurs twice

  41. GOODMAN
    • 3 years ago
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    ez okay myininaya..u have a very beautiful stem and leaf plot...

  42. Zarkon
    • 3 years ago
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    you find the median?

  43. GOODMAN
    • 3 years ago
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    working on it...

  44. myininaya
    • 3 years ago
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    you have an odd number so its just the middle term

  45. myininaya
    • 3 years ago
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    once the set has been ordered from least to greatest

  46. myininaya
    • 3 years ago
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    the set the data the whatever you want to call it

  47. GOODMAN
    • 3 years ago
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    arghhh...i hate puting them in order...im always off a number..

  48. myininaya
    • 3 years ago
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    yes like i was earlier lol

  49. Zarkon
    • 3 years ago
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    do a bubble sort (or quick sort if you are in a hurry) ;)

  50. myininaya
    • 3 years ago
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    if you want to use my stem and leaf you can (eventhough according to zarkon its not a legal stem and leaf) just add one more 5 for 107

  51. Zarkon
    • 3 years ago
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    it is totally illegal...it should be arrested

  52. myininaya
    • 3 years ago
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    what the cops don't know won't hurt them

  53. Zarkon
    • 3 years ago
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    that's right

  54. GOODMAN
    • 3 years ago
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    omg..now ur talking bout cops

  55. myininaya
    • 3 years ago
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    don't worry about them there is a separation of cops and math

  56. Zarkon
    • 3 years ago
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    shouldn't you be finding the median ;)

  57. GOODMAN
    • 3 years ago
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    i still havent gotten them in order..im always making a mistake...can u guys help?

  58. Zarkon
    • 3 years ago
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    {975,1005,1025,1055,1075,1075,1095,1100,1125,1125,1145}

  59. GOODMAN
    • 3 years ago
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    lolz..u did it sooo fast....

  60. GOODMAN
    • 3 years ago
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    1075 is the median

  61. Zarkon
    • 3 years ago
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    yes

  62. Zarkon
    • 3 years ago
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    now find the median of the lower half of the data

  63. GOODMAN
    • 3 years ago
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    1025=q1 1125=q3 rite?

  64. Zarkon
    • 3 years ago
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    yes

  65. GOODMAN
    • 3 years ago
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    YEA!!!!!!!!

  66. Zarkon
    • 3 years ago
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    calculate the IQR

  67. GOODMAN
    • 3 years ago
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    how do we do tat?

  68. Zarkon
    • 3 years ago
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    \[IQR=Q_3-Q_1\]

  69. GOODMAN
    • 3 years ago
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    100

  70. Zarkon
    • 3 years ago
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    yep

  71. Zarkon
    • 3 years ago
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    now compute \[Q_1-1.5\times IQR\] and \[Q_3+1.5\times IQR\]

  72. Zarkon
    • 3 years ago
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    there are called the Lower fence and Upper fence

  73. GOODMAN
    • 3 years ago
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    102350 and 112650

  74. Zarkon
    • 3 years ago
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    no

  75. GOODMAN
    • 3 years ago
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    what did i do now....

  76. Zarkon
    • 3 years ago
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    \[Q_1-1.5\times IQR=1025-1.5\times100=1025-150=875\]

  77. GOODMAN
    • 3 years ago
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    oh....i first multiplied 1025 and 1.5

  78. Zarkon
    • 3 years ago
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    what is the upper fence then ( i gave you the lower fence)

  79. GOODMAN
    • 3 years ago
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    1275?

  80. Zarkon
    • 3 years ago
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    yes

  81. GOODMAN
    • 3 years ago
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    boo ya!!!

  82. Zarkon
    • 3 years ago
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    ok..are there any numbers in your data set that are smaller than 875 or larger than 1275?

  83. GOODMAN
    • 3 years ago
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    ummm.....no

  84. Zarkon
    • 3 years ago
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    correct...therefore there are no outliers

  85. GOODMAN
    • 3 years ago
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    yea!!! okay...now wat about the box and whiskers the pic...

  86. Zarkon
    • 3 years ago
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    |dw:1319594794785:dw|

  87. GOODMAN
    • 3 years ago
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    so tats how we draw it?

  88. Zarkon
    • 3 years ago
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    sort of...hard to write on the picture

  89. Zarkon
    • 3 years ago
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    the line at the bottom is a number line...the vertical lines on the box should correspond the the quartiles. the line out of the box to the left should extend out the the min value and the line out to the right of the box to the max

  90. GOODMAN
    • 3 years ago
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    HUH????????

  91. Zarkon
    • 3 years ago
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    http://ellerbruch.nmu.edu/cs255/jnord/three.gif

  92. GOODMAN
    • 3 years ago
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    ohhhhhhh...tat explains it!! LOL

  93. GOODMAN
    • 3 years ago
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    |dw:1319595179179:dw|

  94. Zarkon
    • 3 years ago
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    nice ;)

  95. GOODMAN
    • 3 years ago
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    yea!!! thanks for ur help!

  96. Zarkon
    • 3 years ago
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    no problem

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is replying to Can someone tell me what button the professor is hitting...

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