anonymous
  • anonymous
BOX AND WHISKER PLOTS!!! BOX AND WHISKER PLOTS!!! @Mathematics
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
{1055, 1075, 1095, 1125, 1005, 975, 1125, 1100, 1145, 1025, 1075}
anonymous
  • anonymous
HEY...can show me how to make one for this...and to find the outliers
Zarkon
  • Zarkon
are you using Tukey’s rule?

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anonymous
  • anonymous
wat is tukeys rule..LOL
anonymous
  • anonymous
we are using matrices....
Zarkon
  • Zarkon
for finding outliers
Zarkon
  • Zarkon
matrices for a box plot?
anonymous
  • anonymous
dunno...wat is tukeys rule..can u teach me?
Zarkon
  • Zarkon
find the quartiles
anonymous
  • anonymous
not ezactly...tas the chapter were on...technically it has nothing to do with matrices which i find funny...YES QUARTILES..FIND THOSE TOO
Zarkon
  • Zarkon
and the interquartile range
anonymous
  • anonymous
YEA..THAT TOOO!! MAN U READ MY PAPER...
Zarkon
  • Zarkon
compute \[Q_1-1.5IQR\] and \[Q_3+1.5IQR\]
anonymous
  • anonymous
WAT ARE THE QUARTILES?
Zarkon
  • Zarkon
do you know how to find the median?
anonymous
  • anonymous
yea...
Zarkon
  • Zarkon
do that...that is \[Q_2\]
anonymous
  • anonymous
okay...then its 975...
Zarkon
  • Zarkon
then find the median of the lower half of the data...that is \[Q_1\] then find the median of the upper half of the data...that is \[Q_3\]
myininaya
  • myininaya
|dw:1319592543903:dw| isn't this a box and whisker thingy? also i think i'm missing an element and i keep going over the data again and again so i don't know which one i'm missing :( i think i;m getting old
Zarkon
  • Zarkon
|dw:1319592983243:dw|
anonymous
  • anonymous
q1 is |dw:1319592990892:dw|its sumthing like tat...
anonymous
  • anonymous
wow..mines a fail
Zarkon
  • Zarkon
remember you need to sort the data in order to find the median
anonymous
  • anonymous
oh ya...lolz
myininaya
  • myininaya
what i made i think is called a stem and leaf thingy ma jigger
Zarkon
  • Zarkon
correct
anonymous
  • anonymous
YEA!!! STEM AND LEAF PLOT!!! lols i hated those
myininaya
  • myininaya
ok zarkon what element am i missing though i have 10 elements he has 11 i have been over his set over and over and i can't figure out which one i'm missing
anonymous
  • anonymous
whose he?
anonymous
  • anonymous
who has 11 elements?
myininaya
  • myininaya
you have 11 elements
anonymous
  • anonymous
ohh....lolz im a girl...wow i got confused tare...
myininaya
  • myininaya
do i know how to count?
Zarkon
  • Zarkon
not sure...but you wouldn't want to write the stem and leaf like that anyway...the stems need to be uniform...yours are not :)
myininaya
  • myininaya
i like my stem and leaf :(
Zarkon
  • Zarkon
1075
myininaya
  • myininaya
no i see 1075
Zarkon
  • Zarkon
there are two of them
myininaya
  • myininaya
oh it occurs twice
anonymous
  • anonymous
ez okay myininaya..u have a very beautiful stem and leaf plot...
Zarkon
  • Zarkon
you find the median?
anonymous
  • anonymous
working on it...
myininaya
  • myininaya
you have an odd number so its just the middle term
myininaya
  • myininaya
once the set has been ordered from least to greatest
myininaya
  • myininaya
the set the data the whatever you want to call it
anonymous
  • anonymous
arghhh...i hate puting them in order...im always off a number..
myininaya
  • myininaya
yes like i was earlier lol
Zarkon
  • Zarkon
do a bubble sort (or quick sort if you are in a hurry) ;)
myininaya
  • myininaya
if you want to use my stem and leaf you can (eventhough according to zarkon its not a legal stem and leaf) just add one more 5 for 107
Zarkon
  • Zarkon
it is totally illegal...it should be arrested
myininaya
  • myininaya
what the cops don't know won't hurt them
Zarkon
  • Zarkon
that's right
anonymous
  • anonymous
omg..now ur talking bout cops
myininaya
  • myininaya
don't worry about them there is a separation of cops and math
Zarkon
  • Zarkon
shouldn't you be finding the median ;)
anonymous
  • anonymous
i still havent gotten them in order..im always making a mistake...can u guys help?
Zarkon
  • Zarkon
{975,1005,1025,1055,1075,1075,1095,1100,1125,1125,1145}
anonymous
  • anonymous
lolz..u did it sooo fast....
anonymous
  • anonymous
1075 is the median
Zarkon
  • Zarkon
yes
Zarkon
  • Zarkon
now find the median of the lower half of the data
anonymous
  • anonymous
1025=q1 1125=q3 rite?
Zarkon
  • Zarkon
yes
anonymous
  • anonymous
YEA!!!!!!!!
Zarkon
  • Zarkon
calculate the IQR
anonymous
  • anonymous
how do we do tat?
Zarkon
  • Zarkon
\[IQR=Q_3-Q_1\]
anonymous
  • anonymous
100
Zarkon
  • Zarkon
yep
Zarkon
  • Zarkon
now compute \[Q_1-1.5\times IQR\] and \[Q_3+1.5\times IQR\]
Zarkon
  • Zarkon
there are called the Lower fence and Upper fence
anonymous
  • anonymous
102350 and 112650
Zarkon
  • Zarkon
no
anonymous
  • anonymous
what did i do now....
Zarkon
  • Zarkon
\[Q_1-1.5\times IQR=1025-1.5\times100=1025-150=875\]
anonymous
  • anonymous
oh....i first multiplied 1025 and 1.5
Zarkon
  • Zarkon
what is the upper fence then ( i gave you the lower fence)
anonymous
  • anonymous
1275?
Zarkon
  • Zarkon
yes
anonymous
  • anonymous
boo ya!!!
Zarkon
  • Zarkon
ok..are there any numbers in your data set that are smaller than 875 or larger than 1275?
anonymous
  • anonymous
ummm.....no
Zarkon
  • Zarkon
correct...therefore there are no outliers
anonymous
  • anonymous
yea!!! okay...now wat about the box and whiskers the pic...
Zarkon
  • Zarkon
|dw:1319594794785:dw|
anonymous
  • anonymous
so tats how we draw it?
Zarkon
  • Zarkon
sort of...hard to write on the picture
Zarkon
  • Zarkon
the line at the bottom is a number line...the vertical lines on the box should correspond the the quartiles. the line out of the box to the left should extend out the the min value and the line out to the right of the box to the max
anonymous
  • anonymous
HUH????????
Zarkon
  • Zarkon
http://ellerbruch.nmu.edu/cs255/jnord/three.gif
anonymous
  • anonymous
ohhhhhhh...tat explains it!! LOL
anonymous
  • anonymous
|dw:1319595179179:dw|
Zarkon
  • Zarkon
nice ;)
anonymous
  • anonymous
yea!!! thanks for ur help!
Zarkon
  • Zarkon
no problem

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