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SHAI_KHAN
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1319608937187:dw

agreene
 3 years ago
Best ResponseYou've already chosen the best response.1why do you keep coming up with integrals I don't want to do. another trig sub question O.o

SHAI_KHAN
 3 years ago
Best ResponseYou've already chosen the best response.0angreene What can I do.. all my subject like this Q..

agreene
 3 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=+Integral+1+%2F%28+x+%28sqrt%283%2Bx%5E2%29%29 click show steps

mathTalk
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{2}1/(x(3+x^2)^(1/2))\] let u = 3+x^2 du= 2xdx (1/2)(1/u)^(1/2)]du (1/2) 2u^(1/2) =u^(1/2) when x = 1 u =4 and when x = 2 u = 7 therefore =7^(1/2)2^(1/2)

agreene
 3 years ago
Best ResponseYou've already chosen the best response.11/(x sqrt(x^2+3)) substitute x = sqrt(3) tan(u) and dx = sqrt(3) sec^2(u) du. which is why i didnt want to do this one, lol
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