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SHAI_KHAN Group TitleBest ResponseYou've already chosen the best response.0
dw:1319608937187:dw
 3 years ago

agreene Group TitleBest ResponseYou've already chosen the best response.1
why do you keep coming up with integrals I don't want to do. another trig sub question O.o
 3 years ago

SHAI_KHAN Group TitleBest ResponseYou've already chosen the best response.0
angreene What can I do.. all my subject like this Q..
 3 years ago

agreene Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=+Integral+1+%2F%28+x+%28sqrt%283%2Bx%5E2%29%29 click show steps
 3 years ago

mathTalk Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{1}^{2}1/(x(3+x^2)^(1/2))\] let u = 3+x^2 du= 2xdx (1/2)(1/u)^(1/2)]du (1/2) 2u^(1/2) =u^(1/2) when x = 1 u =4 and when x = 2 u = 7 therefore =7^(1/2)2^(1/2)
 3 years ago

mathTalk Group TitleBest ResponseYou've already chosen the best response.0
no i'm wrong
 3 years ago

agreene Group TitleBest ResponseYou've already chosen the best response.1
1/(x sqrt(x^2+3)) substitute x = sqrt(3) tan(u) and dx = sqrt(3) sec^2(u) du. which is why i didnt want to do this one, lol
 3 years ago

mathTalk Group TitleBest ResponseYou've already chosen the best response.0
this is bad.
 3 years ago
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