Here's the question you clicked on:
invn177
ok integral of INT/limits 1 to 0/ (e^x)^2
\[\int_0^1 e^{x^2}dx\]
ah it is error function or something like that I can't do it
http://www.wolframalpha.com/input/?i=integration+e^%28x^2%29+from+0+to+1
yeah, i think its like 1/2 sqrt(pi)*error(imaginary) or some such
yep. that's what my calcu says.. 1.462651746 xD
nonono, (e^x)(e^x) or (e^x)^2, integrate that from 1 to 0
And I have a computer right in front of me as well as a ti-84+ so I dont want your calculator or wolfram alpha answers please :)
Oh, that is much simpler. (e^x)^2 = e^2x so: \[\int\limits_{0}^{1}e^{2x}dx=\frac{1}{2}e^2x\] take it to the limits: [1/2*e^(2)]-[1/2*e^(0)]=1/2e^2-1/2 factor it and you have: \[\frac{1}{2}(e^2-1)\]
oh you sure that (e^x)^2=e^2x?
yes, that is one of the properties of exponents