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invn177
 4 years ago
ok integral of INT/limits 1 to 0/ (e^x)^2
invn177
 4 years ago
ok integral of INT/limits 1 to 0/ (e^x)^2

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Ishaan94
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int_0^1 e^{x^2}dx\]

Ishaan94
 4 years ago
Best ResponseYou've already chosen the best response.1ah it is error function or something like that I can't do it

Ishaan94
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=integration+e^%28x^2%29+from+0+to+1

agreene
 4 years ago
Best ResponseYou've already chosen the best response.2yeah, i think its like 1/2 sqrt(pi)*error(imaginary) or some such

hbaldon
 4 years ago
Best ResponseYou've already chosen the best response.0yep. that's what my calcu says.. 1.462651746 xD

invn177
 4 years ago
Best ResponseYou've already chosen the best response.0nonono, (e^x)(e^x) or (e^x)^2, integrate that from 1 to 0

invn177
 4 years ago
Best ResponseYou've already chosen the best response.0And I have a computer right in front of me as well as a ti84+ so I dont want your calculator or wolfram alpha answers please :)

agreene
 4 years ago
Best ResponseYou've already chosen the best response.2Oh, that is much simpler. (e^x)^2 = e^2x so: \[\int\limits_{0}^{1}e^{2x}dx=\frac{1}{2}e^2x\] take it to the limits: [1/2*e^(2)][1/2*e^(0)]=1/2e^21/2 factor it and you have: \[\frac{1}{2}(e^21)\]

invn177
 4 years ago
Best ResponseYou've already chosen the best response.0oh you sure that (e^x)^2=e^2x?

agreene
 4 years ago
Best ResponseYou've already chosen the best response.2yes, that is one of the properties of exponents
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