## invn177 3 years ago ok integral of INT/limits 1 to 0/ (e^x)^2

1. hbaldon

rewrite?

2. Ishaan94

$\int_0^1 e^{x^2}dx$

3. Ishaan94

ah it is error function or something like that I can't do it

4. Ishaan94
5. agreene

yeah, i think its like 1/2 sqrt(pi)*error(imaginary) or some such

6. hbaldon

yep. that's what my calcu says.. 1.462651746 xD

7. mathTalk

what is this now ?

8. invn177

nonono, (e^x)(e^x) or (e^x)^2, integrate that from 1 to 0

9. invn177

And I have a computer right in front of me as well as a ti-84+ so I dont want your calculator or wolfram alpha answers please :)

10. agreene

Oh, that is much simpler. (e^x)^2 = e^2x so: $\int\limits_{0}^{1}e^{2x}dx=\frac{1}{2}e^2x$ take it to the limits: [1/2*e^(2)]-[1/2*e^(0)]=1/2e^2-1/2 factor it and you have: $\frac{1}{2}(e^2-1)$

11. invn177

oh you sure that (e^x)^2=e^2x?

12. agreene

yes, that is one of the properties of exponents

13. invn177

fsho