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ilovecherrypot

  • 3 years ago

What is the slope of the line which passes through (–6, 0) and (4, 0)?

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  1. saifoo.khan
    • 3 years ago
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  2. Teddy_stephie
    • 3 years ago
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    |dw:1319609801076:dw|

  3. mathTalk
    • 3 years ago
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    e^2 cos(pi/2)

  4. fewscrewsmissing
    • 3 years ago
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    \[\Delta Y \div \Delta X\] Or "change in Y over change in X" or "rise over run" So: \[(0 - 0) \div (4--6)\]\[=0 \div 10\]\[=0\]

  5. Teddy_stephie
    • 3 years ago
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    However, the answer is zero, right?

  6. saifoo.khan
    • 3 years ago
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    RIght.

  7. fewscrewsmissing
    • 3 years ago
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    Yes, the slope is 0. Meaning the line will run parallel to the x-axis, offset by whatever constant is added. Generally the equation used is:\[y = mx + c\] or something equivalent. So the line would run parallel to the x-axis at the y value of whatever 'c' is equal to.

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