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anonymous
 4 years ago
Solve this system of equations using the addition method.
3xy=9
2x+y=6 Solve this system of equations using the addition method.
3xy=9
2x+y=6 @Mathematics
anonymous
 4 years ago
Solve this system of equations using the addition method. 3xy=9 2x+y=6 Solve this system of equations using the addition method. 3xy=9 2x+y=6 @Mathematics

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.05x + 0 = 15 x = 3 plug to the first equation 2.3 + y = 6 y = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i would just add the numbers then divide

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first add the equation 1 and 2 so that it will get rid of one of the variable In this example, you got it easy because in equation 1 you have y, and in equation 2 you have y, so the sum of these equations will get rid of y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in case you want to get rid of x first. then you would have to do the following: multiply 1st equation by 2 multiply 2nd equation by 3 so that it would appear like this 6x .... 6x  0x ......

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im sorry im very confused..see im takin algebra online and dnt have a teacher so i have to take tests online and have no idea how to do them

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so you have two equations and two variables which is x, y. They ask you to find those values of x, y so that when you plug them in to any equation, they have to be true. In this case if you plug x = 0 and y = 3. Both equations hold. That's how it goes anyways.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now they asked you to use addition method which means. some how you have to add equation 1 and equation 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03xy=9 + 2x+y=6  5x + 0 = 15 the new equation only has x now. So you know what x is, just plug into any of the equations they gave you, you will get y value.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0give me another problem, i'll explain in more details because this is problem is very simple.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright. this is also simple. Let's change to 4a + 5b = 7 2a + 3b = 9 instead.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now what do you do? I want to know how you do it, then I'll explain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. but the new equation doesn't get rid of any variables right? so your stuck

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to modify the original equations somehow so when adding you will get either 0x or 0y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at this problem you gave me: 4a5b=7 4a+5b=17 notice the 5b (1st) and 5b (2nd equation). when adding the result is 0b. that's why i said they gave you a simple problem. Just adding.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you learn how to modify the equations yet? or just purely adding stuff?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no did learn to modify the equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay then please try to modify this one: 4a + 5b = 7 2a + 3b = 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cnt i dnt understand how to modify im sorry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let's try to modify so when adding I will get 0a ok?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i see first equation have 4a. the 2nd have 2a. ... I need to have some how to have 2nd equation to have 4a. Right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can do this by multiply 2nd equation by 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what's the modified equation now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok the modified (2nd equation) becomes: 4a 6b = 18

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now you can add the first and the modified.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so then id add the 4a and 5b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no no. it's gonna be like this: 4a + 5b = 7 + 4a 6b = 18  0a b = 11

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you only add the a and a... b and b not a and b.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so now you can solve for the b value. Once you have one variable solved, plug to any of the original equation, then bam. That's it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you modify to get rid of b instead of a this time? it's a bit harder, but same method. 4a + 5b = 7 2a + 3b = 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to modify both equations for b.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you will get 6a + 8b = 16?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it doesn't get rid of b does it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need to get help from professor about this. But those problems you gave me. you can just add them directly without modifying anything.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are not clear about the concept of adding.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one thing I can tell you that when adding you must get rid of one of the variables.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no im not im sorry thnks for tryin to help tho

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to go home. sorry
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