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pottersheep
f(x) = x^2. How would I find the coordinates of the graph f(x-3) +1 ?
Do i substitute x^2 into f(x-3) +1 whenever x appears ? so 3(x^2 -3 ) + 1????
f(x) = x^2 f(x-3)+1 = (x-3)^2 +1 = x^2 +9+1
just one modification to it 3(x-3)^2 +1
from where do u get that 3
Your question asks to identify the coordinates of the graph; the graph is going to be an upward parabola, which has been translated to the right 3 units and up 1 unit. i.e., the vertex is (3,1) and is constructed as per the usual conventional upward turning parabola.