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anonymous
 4 years ago
How to solve a probabilitiy when it has or in the problem. Like P (A or B)?
anonymous
 4 years ago
How to solve a probabilitiy when it has or in the problem. Like P (A or B)?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just add the probaility if they are disjoint however take out P(A and B) if the sets are not disjoint.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0E.) was P (A and B) and then F.) is P (A or B). Earlier in the question I did P(A)=230/580 and P(B)=200/580. What should I do to find P (A or B)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0P(A or B) =1P'(AorB) =1 150/580=430/580

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am sorry where did you get the 150 at?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0total P = P(A)+p(B)+P'(A or B)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So if I need to solve for P (B or D) and P (B) was 200/580 and P (D) was 250/580. How do I solve this one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why would the problems be so different? Why did I use 1 in the first one but the second one just added the top numbers?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0P(A+B)= P(A)+P(B)p(aandB)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know you gave me the formula but I dont understand how you got 150 still.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry for confusing you. I was wrong there.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha its ok I just dont get probability at all. So can we start over real quick. I need to find P (A or B). P (A) was 230/580 and P(B) was 200/580.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0simply add the two probabilities ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i am not sure about the intersection.
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