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nubeer
 5 years ago
lim x>0 [(xe^(1/x))/(lnx^sinx)]
anyone plz can help me on this question..
nubeer
 5 years ago
lim x>0 [(xe^(1/x))/(lnx^sinx)] anyone plz can help me on this question..

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0}\frac{e^{\frac{1}{x}}}{\ln(x)^{\sin(x)}}\]??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0}\frac{xe^{\frac{1}{x}}}{\ln(x)^{\sin(x)}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tried using l'hopital's rule and it just go way uglier. the wolf says one way it is zero and the other way is infinity http://www.wolframalpha.com/input/?i=limit+as+x+goes+to+0+%28xe%5E%281%2Fx%29%29%2F%28ln%28x%29%5Esin%28x%29%29
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