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lim x>0 [(xe^(1/x))/(lnx^sinx)]
anyone plz can help me on this question..
 2 years ago
 2 years ago
lim x>0 [(xe^(1/x))/(lnx^sinx)] anyone plz can help me on this question..
 2 years ago
 2 years ago

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satellite73Best ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 0}\frac{e^{\frac{1}{x}}}{\ln(x)^{\sin(x)}}\]??
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 0}\frac{xe^{\frac{1}{x}}}{\ln(x)^{\sin(x)}}\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
tried using l'hopital's rule and it just go way uglier. the wolf says one way it is zero and the other way is infinity http://www.wolframalpha.com/input/?i=limit+as+x+goes+to+0+%28xe%5E%281%2Fx%29%29%2F%28ln%28x%29%5Esin%28x%29%29
 2 years ago
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