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jhartford

  • 4 years ago

Find all real solutions 2y^4 + 7y^3 - 26y^2 +23y - 6 = 0

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  1. misszippy7
    • 4 years ago
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    y = -6 y= 1/2 y=1

  2. jhartford
    • 4 years ago
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    how'd you get that?

  3. misszippy7
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=2y%5E4+%2B+7y%5E3+-+26y%5E2+%2B23y+-+6+%3D+0 LOL.

  4. jhartford
    • 4 years ago
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    haha thanks.

  5. asnaseer
    • 4 years ago
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    If you want to learn how this is done in general, see: http://www.1728.org/quartic2.htm

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