anonymous
  • anonymous
For each of the following sets of ions, rank them from smallest to largest ionic radius.
Chemistry
schrodinger
  • schrodinger
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anonymous
  • anonymous
a. Mg²+,Si⁴-, S²-
anonymous
  • anonymous
Mg2+< S2- < S 4-
anonymous
  • anonymous
do you need a reason too..???????

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anonymous
  • anonymous
no just need help with more if you dnt mind
anonymous
  • anonymous
b. Mg²+, Ca²+,Ba²+ c.F-,Cl-, Br- d.Ba²+,Cu²+,Zn²+ e. Si⁴-, P³-, O²-
anonymous
  • anonymous
ok in anion the greater will be the charge more will be the radius because when we add an electron no. of proton decreases as compare to electron which means nucleous effective charge decreaes as a rseult size increaes in anion more the positive charge less the radius as proton no. increses because of lose of an electron means more nuclear charge which attracts the electron present aND bring closer as a result bond length decreases
anonymous
  • anonymous
conclusion: in anion more charge greater radius in cation more charge smaller radius
anonymous
  • anonymous
as u know down the group bond length increaes and if there is charge also same then we will use normal trend b)Mg2+ < Ca2+

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