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Statistics
The diameters of grapefruits in a certain orchard are normally distributed with a mean of 7.30 inches and a standard deviation of 0.80 inches. Show all work.
(A) What percentage of the grapefruits in this orchard have diameters less than 6.7 inches?
(B) What percentage of the grapefruits in this orchard are larger than 7.20 inches?
What I have wrote out
mean=m=7.30
Standard deviation=s=0.80
(A) what % have diameters less than 6.7
(B) what %are larger than 7.20
 2 years ago
 2 years ago
Statistics The diameters of grapefruits in a certain orchard are normally distributed with a mean of 7.30 inches and a standard deviation of 0.80 inches. Show all work. (A) What percentage of the grapefruits in this orchard have diameters less than 6.7 inches? (B) What percentage of the grapefruits in this orchard are larger than 7.20 inches? What I have wrote out mean=m=7.30 Standard deviation=s=0.80 (A) what % have diameters less than 6.7 (B) what %are larger than 7.20
 2 years ago
 2 years ago

This Question is Closed

amistre64Best ResponseYou've already chosen the best response.2
A is asking: P(X<6.7)
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
good, thats our z score for A
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
we get a negative and we know that it wants the value of everything to the left of it
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
zvalue will probably be called a Pvalue later in the book
 2 years ago

mathTalkBest ResponseYou've already chosen the best response.0
Can we use the bell curve ?
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
yes, mathtalk that is what they are all made of (im in statisticsthe book says elementary statistics my first class of it0
 2 years ago

mathTalkBest ResponseYou've already chosen the best response.0
somebody show how to proceed here
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
so 0.50000.2734(from the table)=
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
its alot to wrap up form previous posts ... but in a nutshell, you get a zscore and look that up in a table to get a value
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
then work it into the question to find an answer
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
.2734 is good, so that should do it for A
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
B is trickier in that it wants values all to the right of z
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
same concept, but we have to adjust our thinking a little to accomodate for it
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
don't we do 0.50000.2734?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
A is the result of .5  .2734
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
for the first one? right.
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
oh ok, then i have 0.2266
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
so then I write it like this right? P(x<6.7)=0.23
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
B needs some care taken to it.dw:1320180861380:dw
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
A asks for a % so we gotta rewrite .2266 as 22.66%
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
that looks good to me
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
ok, on to the second one!
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
lets figure the z score to get started
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
ok, I have been having loading problems, so I thought it was me.
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
wait I am trying to figure it.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
z = (7.27.3)/.8 .... same process, different numbers
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
xmean/stan dev. 7.207.30/0.80
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
01/0.80 0.125/0.80 0.15625
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
got some typos in there... but your on the right track .1/.8 = .125
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
7.2  7.3 = .1 .1/.8 = 1/8 = .125
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
and then: 0.125/0.80 =0.15625
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
no, there is no need to divide it again by .8
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
ok, i see it. ok next step.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
\[z=\frac{x\bar x}{\sigma}\] \[z=\frac{7.207.30}{0.80}\] \[z=\frac{0.10}{0.80}=0.125\]
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
id go with the z=.13 value, but a better result would be that since this is exactly in between .12 and .13 to take the average of the values as well
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
now I go find it in the table.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
yep, we need the value for this z to calculate with
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
thats what i got in my table as well
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
so do we take 0.5000+0.0517?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
we do, and you understand why right?
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
because it is greater, and because it is a positive number
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
close enough, with more practice it should become better to see it :)
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
one way to think of it is to get the value to the left and subtract it from the total value under the curve; the total is 1
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
1  (value to the left of z) = (value to the right of z)
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
because the problem is a greater than, so you have to add the left side of the bell with the amount that is greater than the half.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
yep, that is a very good way to view it. good job ;)
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
well thanks for the medal! (medals).
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
and remember its asking for %
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
which makes it a 55.17%
 2 years ago

Nickie_SBest ResponseYou've already chosen the best response.1
Ok, I have 2 more questions I need help with, and as I am learning maybe i can do most of the work. So here we go to another question, if your p for it.
 2 years ago

amistre64Best ResponseYou've already chosen the best response.2
im good for it .... :)
 2 years ago
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