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anonymous
 5 years ago
Statistics
The diameters of grapefruits in a certain orchard are normally distributed with a mean of 7.30 inches and a standard deviation of 0.80 inches. Show all work.
(A) What percentage of the grapefruits in this orchard have diameters less than 6.7 inches?
(B) What percentage of the grapefruits in this orchard are larger than 7.20 inches?
What I have wrote out
mean=m=7.30
Standard deviation=s=0.80
(A) what % have diameters less than 6.7
(B) what %are larger than 7.20
anonymous
 5 years ago
Statistics The diameters of grapefruits in a certain orchard are normally distributed with a mean of 7.30 inches and a standard deviation of 0.80 inches. Show all work. (A) What percentage of the grapefruits in this orchard have diameters less than 6.7 inches? (B) What percentage of the grapefruits in this orchard are larger than 7.20 inches? What I have wrote out mean=m=7.30 Standard deviation=s=0.80 (A) what % have diameters less than 6.7 (B) what %are larger than 7.20

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2A is asking: P(X<6.7)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2good, thats our z score for A

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we get a negative and we know that it wants the value of everything to the left of it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2zvalue will probably be called a Pvalue later in the book

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can we use the bell curve ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, mathtalk that is what they are all made of (im in statisticsthe book says elementary statistics my first class of it0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0somebody show how to proceed here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 0.50000.2734(from the table)=

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2its alot to wrap up form previous posts ... but in a nutshell, you get a zscore and look that up in a table to get a value

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2then work it into the question to find an answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2.2734 is good, so that should do it for A

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2B is trickier in that it wants values all to the right of z

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2same concept, but we have to adjust our thinking a little to accomodate for it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't we do 0.50000.2734?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2A is the result of .5  .2734

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the first one? right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok, then i have 0.2266

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then I write it like this right? P(x<6.7)=0.23

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2B needs some care taken to it.dw:1320180861380:dw

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2A asks for a % so we gotta rewrite .2266 as 22.66%

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0*100 .2266*100=22.66%

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2that looks good to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, on to the second one!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2lets figure the z score to get started

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, I have been having loading problems, so I thought it was me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait I am trying to figure it.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2z = (7.27.3)/.8 .... same process, different numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0xmean/stan dev. 7.207.30/0.80

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.001/0.80 0.125/0.80 0.15625

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2got some typos in there... but your on the right track .1/.8 = .125

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.27.2  7.3 = .1 .1/.8 = 1/8 = .125

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then: 0.125/0.80 =0.15625

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2no, there is no need to divide it again by .8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, i see it. ok next step.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2\[z=\frac{x\bar x}{\sigma}\] \[z=\frac{7.207.30}{0.80}\] \[z=\frac{0.10}{0.80}=0.125\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2id go with the z=.13 value, but a better result would be that since this is exactly in between .12 and .13 to take the average of the values as well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now I go find it in the table.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2yep, we need the value for this z to calculate with

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2thats what i got in my table as well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so do we take 0.5000+0.0517?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we do, and you understand why right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because it is greater, and because it is a positive number

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2close enough, with more practice it should become better to see it :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2one way to think of it is to get the value to the left and subtract it from the total value under the curve; the total is 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.21  (value to the left of z) = (value to the right of z)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because the problem is a greater than, so you have to add the left side of the bell with the amount that is greater than the half.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2yep, that is a very good way to view it. good job ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well thanks for the medal! (medals).

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2and remember its asking for %

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which makes it a 55.17%

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, I have 2 more questions I need help with, and as I am learning maybe i can do most of the work. So here we go to another question, if your p for it.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2im good for it .... :)
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