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becca18 Group Title

Directions say: Determine whether the lines are intersecting, parallel or the same (check slopes) How many points in common, Give solution if any: 3x-y=2 6x-2y=3 Explain.

  • 3 years ago
  • 3 years ago

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  1. hbaldon Group Title
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    equation of a line: y=mx + b equating your givens: y=3x-2 2y=6x-3 (divide both sides by 2 to eliminate constant 2. so we will get:) y=3x-3/2 lines are parallel.. you can graph it by substituting x. let's say from -3 to 3.. slopes: both slopes are 3.

    • 3 years ago
  2. becca18 Group Title
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    I still don't understand.. But thanks!

    • 3 years ago
  3. hbaldon Group Title
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    what part?

    • 3 years ago
  4. becca18 Group Title
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    All of it.. could you draw it?

    • 3 years ago
  5. hbaldon Group Title
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    ok, wait. this is not easy drawing. xD

    • 3 years ago
  6. becca18 Group Title
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    Well it's okay

    • 3 years ago
  7. hbaldon Group Title
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    did you know why i came up with y=3x-2 from 3x-y=2?

    • 3 years ago
  8. becca18 Group Title
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    y=mx+b?

    • 3 years ago
  9. hbaldon Group Title
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    yep..

    • 3 years ago
  10. becca18 Group Title
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    but then wouldn't be -y=-3x+2 & -2y=-6x+3?

    • 3 years ago
  11. hbaldon Group Title
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    because if you transfer a number from other side, the sign will change. let's say -2+3=1 if you transfer -2 to the right side, it will be 3=1+2..

    • 3 years ago
  12. hbaldon Group Title
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    -2+3=1.. if you transfer -2 to the right side, it will be 3=1+2

    • 3 years ago
  13. hbaldon Group Title
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    the red line is your y=3x-2 and the green line is your y=3x-3/2 and for the slope, from the equation y=mx+b, m is the slope. so the slope for the two linear equations is 3. the rest are in the images. :D http://www.fileden.com/files/2007/10/19/1523433/IMG_0022.PNG http://www.fileden.com/files/2007/10/19/1523433/SAM_1559.JPG

    • 3 years ago
  14. becca18 Group Title
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    Thank you sooooo much! you did so much work! Lol Pretty handwriting too!(:

    • 3 years ago
  15. hbaldon Group Title
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    lol. no problemo.. just trying to help. :D

    • 3 years ago
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