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ErkoT
Logarithm bases are in () Solve: Log(x)log(2x)2=log(4x)2
2logx(logx + logx )=8logx log2x=4 e^log2x = e^2 2x=e^2 x= (e^2)/2
o^log(4x)2=0, therefore the other are zeroes too?
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