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ErkoT

  • 4 years ago

Logarithm bases are in () Solve: Log(x)log(2x)2=log(4x)2

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  1. mathTalk
    • 4 years ago
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    2logx(logx + logx )=8logx log2x=4 e^log2x = e^2 2x=e^2 x= (e^2)/2

  2. mark_o.
    • 4 years ago
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    o^log(4x)2=0, therefore the other are zeroes too?

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