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Sariah
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Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
@Mathematics
 2 years ago
 2 years ago
Sariah Group Title
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. @Mathematics
 2 years ago
 2 years ago

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Sariah Group TitleBest ResponseYou've already chosen the best response.0
Please only i need help to finish this math work,,,
 2 years ago

NickRowell Group TitleBest ResponseYou've already chosen the best response.0
denominator in the second fraction is the first denominator squared... (3x/x1)  (x4/x^22x+1) = (3x/x1)  (x4/(x  1)^2) Thus we will need to multiply the first fraction by (x  1) / (x  1)... (3x(x  1)/(x  1)^2)  (x4/(x  1)^2) and put it all over the same denominator: [(3x(x  1)  (x  4)] / (x  1)^2 Now expand the numerator and simplify... [(3x(x  1)  (x  4)] / (x  1)^2 = (3x^2  3x  x + 4) / (x  1)^2 = (3x^2  4x + 4) / (x  1)^2 Nothing more can be done with this one...that's the answer.
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Nick can you keep help me?
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
asnasser please help me
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
What are the answer to question 9,10,13,17,18 and 19...
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Iam not good for math...
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}\frac{49}{x}}\]first simplify numerator: \[\frac{4}{x}+\frac{7}{x^{2}}=\frac{4x+7}{x^{2}}\]next simplify the denominator: \[\frac{16}{x^{2}}\frac{49}{x}=\frac{1649x}{x^{2}}\]now use the following rule for fraction division:\[\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}\]and you will get: \[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}\frac{49}{x}}=\frac{4x+7}{x^{2}}/\frac{1649x}{x^{2}}=\frac{4x+7}{x^{2}}*\frac{x^{2}}{1649x}\]\[=\frac{4x+7}{1649x}\]
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
The D is the right answer then...
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Question 18?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
for question 9, a polynomial is defined as:\[c_0x^{0}+c_1x^{1}+c_2x^{2}+...+c_nx^{n}\] all the "c" terms are constants. it's "degree" is defined as the highest "power" of x that you have  in the case above it is a polynomial of degree "n". e.g. 2x+9x^2 is a polynomial of degree 2. you should be able to answer question 9 with this information.
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
question 13 is fairly easy  you just made a simple mistake when multiplying the last terms
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Iam sure that Question 9 the a is not the answer right...
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Please dear, give me the answers...
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
correct  the only term given in the polynomial in question 9 is\[2\pi\]which is just a constant. so there are no powers of x in this.
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
if it is not the a, what is the right answer?
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Do you want a medall? please help with the answers... I do not understand math....Iam studing othe thing....but i selected elective math and it was a wrong
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
I am not looking for a medal  I am here to try and you understand maths. If you are not interested in maths then I guess there is no point in me trying to explain it to you.
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
But if you know the answers... help me then with the answers...
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Thanks dear....can i pay to you if you want... but i need answer this....
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
I can try and teach you how to solve these yourself. you may think its very complicated but it is fairly straight forward and it will give you greater satisfaction when you know that you can work these out yourself. I am not looking for any money or medals. Let me know if you wish to learn.
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
ok... thanks
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Really you are right...
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
ok  good  lets start with question 9
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Ok dear... where are you from?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
what do you think is the "degree" of the following polynomial?\[9x100x^{3}\] (I live in the UK)
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Ok i live in Sweden
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
are you thinking Sariah?
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Yes...but it is very dificult...
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
ok  the answer here is 3 because the term with the highest power is "100x^3". you only need to look at the powers of x  you can completely ignore the coefficients (i.e. ignore the 100 which x^3 is multiplied by)
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
lets try one more: what is the degree of this polynomial?\[99+3x\]
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
the answer is "1" because the highest power of x here is in the term "3x".\[x = x^1\] similarly, the polynomial: 123 has a degree of "0" because if has no "x"'s in it  just a constant. you should now be able to answer question 9.
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
If you don´t want keep helping me, don´t worry! But thanks anyway...Really for me this assignment is dificult... you are a very good person....´couse i don,t have idea...
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Yes you are right
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
I think the question 9 is D
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Ok teacher....
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
ok Sariah I need to go and eat something now  good luck with the future and be more positive in your own abilities!
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Ok dear... Have a nice day...
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
can i have your Email?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
sure  it's openstudy@anjum.otherinbox.com by the way  just so that you don't get the wrong impression  I am a VERY happily married man :)
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Ok Taht is good....Good luck! If i have question in the fucture, can i send you the Email to you? or what do you think?
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.1
no problem  got to go now  should be back here in about 2 hours....
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
I see you are very good man... i wish every one be like you... Bye Bye!
 2 years ago

Sariah Group TitleBest ResponseYou've already chosen the best response.0
Not today maybe but in the end of november... is it ok... or one day of this.. bye and keep being so you are
 2 years ago
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