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Sariah

Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. @Mathematics

  • 2 years ago
  • 2 years ago

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  1. Sariah
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    Please only i need help to finish this math work,,,

    • 2 years ago
  2. NickRowell
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    denominator in the second fraction is the first denominator squared... (3x/x-1) - (x-4/x^2-2x+1) = (3x/x-1) - (x-4/(x - 1)^2) Thus we will need to multiply the first fraction by (x - 1) / (x - 1)... (3x(x - 1)/(x - 1)^2) - (x-4/(x - 1)^2) and put it all over the same denominator: [(3x(x - 1) - (x - 4)] / (x - 1)^2 Now expand the numerator and simplify... [(3x(x - 1) - (x - 4)] / (x - 1)^2 = (3x^2 - 3x - x + 4) / (x - 1)^2 = (3x^2 - 4x + 4) / (x - 1)^2 Nothing more can be done with this one...that's the answer.

    • 2 years ago
  3. Hero
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    sigh

    • 2 years ago
  4. Sariah
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    Nick can you keep help me?

    • 2 years ago
  5. Sariah
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    asnasser please help me

    • 2 years ago
  6. Sariah
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    What are the answer to question 9,10,13,17,18 and 19...

    • 2 years ago
  7. Sariah
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    Iam not good for math...

    • 2 years ago
  8. asnaseer
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    \[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}\]first simplify numerator: \[\frac{4}{x}+\frac{7}{x^{2}}=\frac{4x+7}{x^{2}}\]next simplify the denominator: \[\frac{16}{x^{2}}-\frac{49}{x}=\frac{16-49x}{x^{2}}\]now use the following rule for fraction division:\[\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}\]and you will get: \[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}=\frac{4x+7}{x^{2}}/\frac{16-49x}{x^{2}}=\frac{4x+7}{x^{2}}*\frac{x^{2}}{16-49x}\]\[=\frac{4x+7}{16-49x}\]

    • 2 years ago
  9. Sariah
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    The D is the right answer then...

    • 2 years ago
  10. Sariah
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    Question 18?

    • 2 years ago
  11. asnaseer
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    for question 9, a polynomial is defined as:\[c_0x^{0}+c_1x^{1}+c_2x^{2}+...+c_nx^{n}\] all the "c" terms are constants. it's "degree" is defined as the highest "power" of x that you have - in the case above it is a polynomial of degree "n". e.g. 2x+9x^2 is a polynomial of degree 2. you should be able to answer question 9 with this information.

    • 2 years ago
  12. Sariah
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    ok

    • 2 years ago
  13. asnaseer
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    question 13 is fairly easy - you just made a simple mistake when multiplying the last terms

    • 2 years ago
  14. Sariah
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    Iam sure that Question 9 the a is not the answer right...

    • 2 years ago
  15. Sariah
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    Please dear, give me the answers...

    • 2 years ago
  16. asnaseer
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    correct - the only term given in the polynomial in question 9 is\[-2\pi\]which is just a constant. so there are no powers of x in this.

    • 2 years ago
  17. Sariah
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    if it is not the a, what is the right answer?

    • 2 years ago
  18. Sariah
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    Do you want a medall? please help with the answers... I do not understand math....Iam studing othe thing....but i selected elective math and it was a wrong

    • 2 years ago
  19. asnaseer
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    I am not looking for a medal - I am here to try and you understand maths. If you are not interested in maths then I guess there is no point in me trying to explain it to you.

    • 2 years ago
  20. Sariah
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    Ok sorry...

    • 2 years ago
  21. Sariah
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    But if you know the answers... help me then with the answers...

    • 2 years ago
  22. Sariah
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    Thanks dear....can i pay to you if you want... but i need answer this....

    • 2 years ago
  23. asnaseer
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    I can try and teach you how to solve these yourself. you may think its very complicated but it is fairly straight forward and it will give you greater satisfaction when you know that you can work these out yourself. I am not looking for any money or medals. Let me know if you wish to learn.

    • 2 years ago
  24. Sariah
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    ok... thanks

    • 2 years ago
  25. Sariah
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    Really you are right...

    • 2 years ago
  26. asnaseer
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    ok - good - lets start with question 9

    • 2 years ago
  27. Sariah
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    Ok dear... where are you from?

    • 2 years ago
  28. asnaseer
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    what do you think is the "degree" of the following polynomial?\[9x-100x^{3}\] (I live in the UK)

    • 2 years ago
  29. Sariah
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    Ok i live in Sweden

    • 2 years ago
  30. asnaseer
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    are you thinking Sariah?

    • 2 years ago
  31. Sariah
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    Yes...but it is very dificult...

    • 2 years ago
  32. asnaseer
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    ok - the answer here is 3 because the term with the highest power is "-100x^3". you only need to look at the powers of x - you can completely ignore the coefficients (i.e. ignore the -100 which x^3 is multiplied by)

    • 2 years ago
  33. asnaseer
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    lets try one more: what is the degree of this polynomial?\[99+3x\]

    • 2 years ago
  34. asnaseer
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    the answer is "1" because the highest power of x here is in the term "3x".\[x = x^1\] similarly, the polynomial: 123 has a degree of "0" because if has no "x"'s in it - just a constant. you should now be able to answer question 9.

    • 2 years ago
  35. Sariah
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    If you don´t want keep helping me, don´t worry! But thanks anyway...Really for me this assignment is dificult... you are a very good person....´couse i don,t have idea...

    • 2 years ago
  36. Sariah
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    Yes you are right

    • 2 years ago
  37. Sariah
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    I think the question 9 is D

    • 2 years ago
  38. asnaseer
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    correct!

    • 2 years ago
  39. Sariah
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    Ok teacher....

    • 2 years ago
  40. asnaseer
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    ok Sariah I need to go and eat something now - good luck with the future and be more positive in your own abilities!

    • 2 years ago
  41. Sariah
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    Ok dear... Have a nice day...

    • 2 years ago
  42. Sariah
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    can i have your E-mail?

    • 2 years ago
  43. asnaseer
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    sure - it's openstudy@anjum.otherinbox.com by the way - just so that you don't get the wrong impression - I am a VERY happily married man :-)

    • 2 years ago
  44. Sariah
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    Ok Taht is good....Good luck! If i have question in the fucture, can i send you the E-mail to you? or what do you think?

    • 2 years ago
  45. asnaseer
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    no problem - got to go now - should be back here in about 2 hours....

    • 2 years ago
  46. Sariah
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    I see you are very good man... i wish every one be like you... Bye Bye!

    • 2 years ago
  47. Sariah
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    Not today maybe but in the end of november... is it ok... or one day of this.. bye and keep being so you are

    • 2 years ago
  48. Sariah
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    Bye Bye"

    • 2 years ago
  49. Hero
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    What the?

    • 2 years ago
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