anonymous
  • anonymous
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. @Mathematics
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Please only i need help to finish this math work,,,
anonymous
  • anonymous
denominator in the second fraction is the first denominator squared... (3x/x-1) - (x-4/x^2-2x+1) = (3x/x-1) - (x-4/(x - 1)^2) Thus we will need to multiply the first fraction by (x - 1) / (x - 1)... (3x(x - 1)/(x - 1)^2) - (x-4/(x - 1)^2) and put it all over the same denominator: [(3x(x - 1) - (x - 4)] / (x - 1)^2 Now expand the numerator and simplify... [(3x(x - 1) - (x - 4)] / (x - 1)^2 = (3x^2 - 3x - x + 4) / (x - 1)^2 = (3x^2 - 4x + 4) / (x - 1)^2 Nothing more can be done with this one...that's the answer.
Hero
  • Hero
sigh

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anonymous
  • anonymous
Nick can you keep help me?
anonymous
  • anonymous
asnasser please help me
anonymous
  • anonymous
What are the answer to question 9,10,13,17,18 and 19...
anonymous
  • anonymous
Iam not good for math...
asnaseer
  • asnaseer
\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}\]first simplify numerator: \[\frac{4}{x}+\frac{7}{x^{2}}=\frac{4x+7}{x^{2}}\]next simplify the denominator: \[\frac{16}{x^{2}}-\frac{49}{x}=\frac{16-49x}{x^{2}}\]now use the following rule for fraction division:\[\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}\]and you will get: \[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}=\frac{4x+7}{x^{2}}/\frac{16-49x}{x^{2}}=\frac{4x+7}{x^{2}}*\frac{x^{2}}{16-49x}\]\[=\frac{4x+7}{16-49x}\]
anonymous
  • anonymous
The D is the right answer then...
anonymous
  • anonymous
Question 18?
asnaseer
  • asnaseer
for question 9, a polynomial is defined as:\[c_0x^{0}+c_1x^{1}+c_2x^{2}+...+c_nx^{n}\] all the "c" terms are constants. it's "degree" is defined as the highest "power" of x that you have - in the case above it is a polynomial of degree "n". e.g. 2x+9x^2 is a polynomial of degree 2. you should be able to answer question 9 with this information.
anonymous
  • anonymous
ok
asnaseer
  • asnaseer
question 13 is fairly easy - you just made a simple mistake when multiplying the last terms
anonymous
  • anonymous
Iam sure that Question 9 the a is not the answer right...
anonymous
  • anonymous
Please dear, give me the answers...
asnaseer
  • asnaseer
correct - the only term given in the polynomial in question 9 is\[-2\pi\]which is just a constant. so there are no powers of x in this.
anonymous
  • anonymous
if it is not the a, what is the right answer?
anonymous
  • anonymous
Do you want a medall? please help with the answers... I do not understand math....Iam studing othe thing....but i selected elective math and it was a wrong
asnaseer
  • asnaseer
I am not looking for a medal - I am here to try and you understand maths. If you are not interested in maths then I guess there is no point in me trying to explain it to you.
anonymous
  • anonymous
Ok sorry...
anonymous
  • anonymous
But if you know the answers... help me then with the answers...
anonymous
  • anonymous
Thanks dear....can i pay to you if you want... but i need answer this....
asnaseer
  • asnaseer
I can try and teach you how to solve these yourself. you may think its very complicated but it is fairly straight forward and it will give you greater satisfaction when you know that you can work these out yourself. I am not looking for any money or medals. Let me know if you wish to learn.
anonymous
  • anonymous
ok... thanks
anonymous
  • anonymous
Really you are right...
asnaseer
  • asnaseer
ok - good - lets start with question 9
anonymous
  • anonymous
Ok dear... where are you from?
asnaseer
  • asnaseer
what do you think is the "degree" of the following polynomial?\[9x-100x^{3}\] (I live in the UK)
anonymous
  • anonymous
Ok i live in Sweden
asnaseer
  • asnaseer
are you thinking Sariah?
anonymous
  • anonymous
Yes...but it is very dificult...
asnaseer
  • asnaseer
ok - the answer here is 3 because the term with the highest power is "-100x^3". you only need to look at the powers of x - you can completely ignore the coefficients (i.e. ignore the -100 which x^3 is multiplied by)
asnaseer
  • asnaseer
lets try one more: what is the degree of this polynomial?\[99+3x\]
asnaseer
  • asnaseer
the answer is "1" because the highest power of x here is in the term "3x".\[x = x^1\] similarly, the polynomial: 123 has a degree of "0" because if has no "x"'s in it - just a constant. you should now be able to answer question 9.
anonymous
  • anonymous
If you don´t want keep helping me, don´t worry! But thanks anyway...Really for me this assignment is dificult... you are a very good person....´couse i don,t have idea...
anonymous
  • anonymous
Yes you are right
anonymous
  • anonymous
I think the question 9 is D
asnaseer
  • asnaseer
correct!
anonymous
  • anonymous
Ok teacher....
asnaseer
  • asnaseer
ok Sariah I need to go and eat something now - good luck with the future and be more positive in your own abilities!
anonymous
  • anonymous
Ok dear... Have a nice day...
anonymous
  • anonymous
can i have your E-mail?
asnaseer
  • asnaseer
sure - it's openstudy@anjum.otherinbox.com by the way - just so that you don't get the wrong impression - I am a VERY happily married man :-)
anonymous
  • anonymous
Ok Taht is good....Good luck! If i have question in the fucture, can i send you the E-mail to you? or what do you think?
asnaseer
  • asnaseer
no problem - got to go now - should be back here in about 2 hours....
anonymous
  • anonymous
I see you are very good man... i wish every one be like you... Bye Bye!
anonymous
  • anonymous
Not today maybe but in the end of november... is it ok... or one day of this.. bye and keep being so you are
anonymous
  • anonymous
Bye Bye"
Hero
  • Hero
What the?

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