Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
@Mathematics

- anonymous

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- schrodinger

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- anonymous

Please only i need help to finish this math work,,,

- anonymous

denominator in the second fraction is the first denominator squared...
(3x/x-1) - (x-4/x^2-2x+1) =
(3x/x-1) - (x-4/(x - 1)^2)
Thus we will need to multiply the first fraction by (x - 1) / (x - 1)...
(3x(x - 1)/(x - 1)^2) - (x-4/(x - 1)^2) and put it all over the same denominator:
[(3x(x - 1) - (x - 4)] / (x - 1)^2
Now expand the numerator and simplify...
[(3x(x - 1) - (x - 4)] / (x - 1)^2 =
(3x^2 - 3x - x + 4) / (x - 1)^2 =
(3x^2 - 4x + 4) / (x - 1)^2
Nothing more can be done with this one...that's the answer.

- Hero

sigh

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## More answers

- anonymous

Nick can you keep help me?

- anonymous

asnasser please help me

- anonymous

What are the answer to question 9,10,13,17,18 and 19...

- anonymous

Iam not good for math...

- asnaseer

\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}\]first simplify numerator:
\[\frac{4}{x}+\frac{7}{x^{2}}=\frac{4x+7}{x^{2}}\]next simplify the denominator:
\[\frac{16}{x^{2}}-\frac{49}{x}=\frac{16-49x}{x^{2}}\]now use the following rule for fraction division:\[\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}\]and you will get:
\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}=\frac{4x+7}{x^{2}}/\frac{16-49x}{x^{2}}=\frac{4x+7}{x^{2}}*\frac{x^{2}}{16-49x}\]\[=\frac{4x+7}{16-49x}\]

- anonymous

The D is the right answer then...

- anonymous

Question 18?

- asnaseer

for question 9, a polynomial is defined as:\[c_0x^{0}+c_1x^{1}+c_2x^{2}+...+c_nx^{n}\]
all the "c" terms are constants. it's "degree" is defined as the highest "power" of x that you have - in the case above it is a polynomial of degree "n".
e.g. 2x+9x^2 is a polynomial of degree 2.
you should be able to answer question 9 with this information.

- anonymous

ok

- asnaseer

question 13 is fairly easy - you just made a simple mistake when multiplying the last terms

- anonymous

Iam sure that Question 9 the a is not the answer right...

- anonymous

Please dear, give me the answers...

- asnaseer

correct - the only term given in the polynomial in question 9 is\[-2\pi\]which is just a constant. so there are no powers of x in this.

- anonymous

if it is not the a, what is the right answer?

- anonymous

Do you want a medall? please help with the answers... I do not understand math....Iam studing othe thing....but i selected elective math and it was
a wrong

- asnaseer

I am not looking for a medal - I am here to try and you understand maths. If you are not interested in maths then I guess there is no point in me trying to explain it to you.

- anonymous

Ok sorry...

- anonymous

But if you know the answers... help me then with the answers...

- anonymous

Thanks dear....can i pay to you if you want... but i need answer this....

- asnaseer

I can try and teach you how to solve these yourself. you may think its very complicated but it is fairly straight forward and it will give you greater satisfaction when you know that you can work these out yourself.
I am not looking for any money or medals.
Let me know if you wish to learn.

- anonymous

ok... thanks

- anonymous

Really you are right...

- asnaseer

ok - good - lets start with question 9

- anonymous

Ok dear... where are you from?

- asnaseer

what do you think is the "degree" of the following polynomial?\[9x-100x^{3}\]
(I live in the UK)

- anonymous

Ok i live in Sweden

- asnaseer

are you thinking Sariah?

- anonymous

Yes...but it is very dificult...

- asnaseer

ok - the answer here is 3 because the term with the highest power is "-100x^3".
you only need to look at the powers of x - you can completely ignore the coefficients (i.e. ignore the -100 which x^3 is multiplied by)

- asnaseer

lets try one more: what is the degree of this polynomial?\[99+3x\]

- asnaseer

the answer is "1" because the highest power of x here is in the term "3x".\[x = x^1\]
similarly, the polynomial:
123
has a degree of "0" because if has no "x"'s in it - just a constant.
you should now be able to answer question 9.

- anonymous

If you don´t want keep helping me, don´t worry! But thanks anyway...Really for me this assignment is dificult... you are a very good person....´couse i don,t have idea...

- anonymous

Yes you are right

- anonymous

I think the question 9 is D

- asnaseer

correct!

- anonymous

Ok teacher....

- asnaseer

ok Sariah I need to go and eat something now - good luck with the future and be more positive in your own abilities!

- anonymous

Ok dear... Have a nice day...

- anonymous

can i have your E-mail?

- asnaseer

sure - it's openstudy@anjum.otherinbox.com
by the way - just so that you don't get the wrong impression - I am a VERY happily married man :-)

- anonymous

Ok
Taht is good....Good luck! If i have question in the fucture, can i send you the E-mail to you? or what do you think?

- asnaseer

no problem - got to go now - should be back here in about 2 hours....

- anonymous

I see you are very good man... i wish every one be like you... Bye Bye!

- anonymous

Not today maybe but in the end of november... is it ok... or one day of this.. bye and keep being so you are

- anonymous

Bye Bye"

- Hero

What the?

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