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anonymous
 4 years ago
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
@Mathematics
anonymous
 4 years ago
Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form. @Mathematics

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please only i need help to finish this math work,,,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0denominator in the second fraction is the first denominator squared... (3x/x1)  (x4/x^22x+1) = (3x/x1)  (x4/(x  1)^2) Thus we will need to multiply the first fraction by (x  1) / (x  1)... (3x(x  1)/(x  1)^2)  (x4/(x  1)^2) and put it all over the same denominator: [(3x(x  1)  (x  4)] / (x  1)^2 Now expand the numerator and simplify... [(3x(x  1)  (x  4)] / (x  1)^2 = (3x^2  3x  x + 4) / (x  1)^2 = (3x^2  4x + 4) / (x  1)^2 Nothing more can be done with this one...that's the answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nick can you keep help me?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0asnasser please help me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What are the answer to question 9,10,13,17,18 and 19...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Iam not good for math...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}\frac{49}{x}}\]first simplify numerator: \[\frac{4}{x}+\frac{7}{x^{2}}=\frac{4x+7}{x^{2}}\]next simplify the denominator: \[\frac{16}{x^{2}}\frac{49}{x}=\frac{1649x}{x^{2}}\]now use the following rule for fraction division:\[\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}\]and you will get: \[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}\frac{49}{x}}=\frac{4x+7}{x^{2}}/\frac{1649x}{x^{2}}=\frac{4x+7}{x^{2}}*\frac{x^{2}}{1649x}\]\[=\frac{4x+7}{1649x}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The D is the right answer then...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1for question 9, a polynomial is defined as:\[c_0x^{0}+c_1x^{1}+c_2x^{2}+...+c_nx^{n}\] all the "c" terms are constants. it's "degree" is defined as the highest "power" of x that you have  in the case above it is a polynomial of degree "n". e.g. 2x+9x^2 is a polynomial of degree 2. you should be able to answer question 9 with this information.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1question 13 is fairly easy  you just made a simple mistake when multiplying the last terms

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Iam sure that Question 9 the a is not the answer right...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please dear, give me the answers...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1correct  the only term given in the polynomial in question 9 is\[2\pi\]which is just a constant. so there are no powers of x in this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if it is not the a, what is the right answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you want a medall? please help with the answers... I do not understand math....Iam studing othe thing....but i selected elective math and it was a wrong

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1I am not looking for a medal  I am here to try and you understand maths. If you are not interested in maths then I guess there is no point in me trying to explain it to you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But if you know the answers... help me then with the answers...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks dear....can i pay to you if you want... but i need answer this....

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1I can try and teach you how to solve these yourself. you may think its very complicated but it is fairly straight forward and it will give you greater satisfaction when you know that you can work these out yourself. I am not looking for any money or medals. Let me know if you wish to learn.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Really you are right...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok  good  lets start with question 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok dear... where are you from?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1what do you think is the "degree" of the following polynomial?\[9x100x^{3}\] (I live in the UK)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1are you thinking Sariah?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes...but it is very dificult...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok  the answer here is 3 because the term with the highest power is "100x^3". you only need to look at the powers of x  you can completely ignore the coefficients (i.e. ignore the 100 which x^3 is multiplied by)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1lets try one more: what is the degree of this polynomial?\[99+3x\]

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1the answer is "1" because the highest power of x here is in the term "3x".\[x = x^1\] similarly, the polynomial: 123 has a degree of "0" because if has no "x"'s in it  just a constant. you should now be able to answer question 9.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you don´t want keep helping me, don´t worry! But thanks anyway...Really for me this assignment is dificult... you are a very good person....´couse i don,t have idea...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think the question 9 is D

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1ok Sariah I need to go and eat something now  good luck with the future and be more positive in your own abilities!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok dear... Have a nice day...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i have your Email?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1sure  it's openstudy@anjum.otherinbox.com by the way  just so that you don't get the wrong impression  I am a VERY happily married man :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok Taht is good....Good luck! If i have question in the fucture, can i send you the Email to you? or what do you think?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1no problem  got to go now  should be back here in about 2 hours....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I see you are very good man... i wish every one be like you... Bye Bye!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Not today maybe but in the end of november... is it ok... or one day of this.. bye and keep being so you are
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