Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Is this set a basis to R3? [1] [3] [0] [2] [2] [0] [3] [1] [1] What method is used? Thank You

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

For vectors to belong to the set of basis 1. they should be linearly independent 2. They should span the space R3.
Okay, would proving the determinant is non-zero be sufficient?
That would probably prove that they are linearly independent right? you will have to show that for any point (a,b,c) in R3 (a,b,c) = k1v1+k2v2+k3v3

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

in addition.
Yes i see. Linear independence would be proved. After making Linear combinations would i then sub in a=0, b=0 and c=0 to see if k1=k2=k3=0?
yess.

Not the answer you are looking for?

Search for more explanations.

Ask your own question