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eashmore
 3 years ago
Best ResponseYou've already chosen the best response.0What do you need to do with the system?

greenchild623
 3 years ago
Best ResponseYou've already chosen the best response.0solve for x and y

eashmore
 3 years ago
Best ResponseYou've already chosen the best response.0Is the system\[\begin{matrix}14  2 = y7x \\ 2x = 10y + 4\end{matrix}\]

eashmore
 3 years ago
Best ResponseYou've already chosen the best response.0Do you have to use any particular method?

greenchild623
 3 years ago
Best ResponseYou've already chosen the best response.0sorry.... it is: 14=20y7x 10y +4 = 2x

greenchild623
 3 years ago
Best ResponseYou've already chosen the best response.0solve by elimination....

eashmore
 3 years ago
Best ResponseYou've already chosen the best response.0Weird. I replied to this but my answer isn't showing up. Let me retype it real fast.

eashmore
 3 years ago
Best ResponseYou've already chosen the best response.0First, we need to solve the first equation for x. We get\[x = (20/7)y + 2\] Then we substitute this expression into the second equation. This yields \[10y  2((20/7)y + 2) = 4\]Solve this for y and plug the value of y back into our expression for x. Let me know what you get.
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