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eashmoreBest ResponseYou've already chosen the best response.0
What do you need to do with the system?
 2 years ago

greenchild623Best ResponseYou've already chosen the best response.0
solve for x and y
 2 years ago

eashmoreBest ResponseYou've already chosen the best response.0
Is the system\[\begin{matrix}14  2 = y7x \\ 2x = 10y + 4\end{matrix}\]
 2 years ago

eashmoreBest ResponseYou've already chosen the best response.0
Do you have to use any particular method?
 2 years ago

greenchild623Best ResponseYou've already chosen the best response.0
sorry.... it is: 14=20y7x 10y +4 = 2x
 2 years ago

greenchild623Best ResponseYou've already chosen the best response.0
solve by elimination....
 2 years ago

eashmoreBest ResponseYou've already chosen the best response.0
Weird. I replied to this but my answer isn't showing up. Let me retype it real fast.
 2 years ago

eashmoreBest ResponseYou've already chosen the best response.0
First, we need to solve the first equation for x. We get\[x = (20/7)y + 2\] Then we substitute this expression into the second equation. This yields \[10y  2((20/7)y + 2) = 4\]Solve this for y and plug the value of y back into our expression for x. Let me know what you get.
 2 years ago
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