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anonymous
 4 years ago
Use the elimination method to solve the following system of equations. x + 3y – z = 2 x – 2y + 3z = 7 x + 2y – 5z = –21
anonymous
 4 years ago
Use the elimination method to solve the following system of equations. x + 3y – z = 2 x – 2y + 3z = 7 x + 2y – 5z = –21

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well here, x + 3y – z=–21........................1 2 x – 2y + 3z=21,,,,,,,,,,,,,,,,,,,,,,,2 7 x + 2y – 5z=21 ..........................3 now multiply eqn 1 by 2 2x+6y2z=42.........................4 subtrating 24 8y+5z=21..............................5 multiply eqn 1 by 7 7x+21y7z=147........................7 subtrating 3  6 19y+2z=126.............................8 z=(19y+126)/2.........................9 substituting value of z in 5 8y+{5(19y+126)/2}=21................................... now get value of y substitute the value of y in eqn 5 get value of z substitute value of y and z in 1 get value of x ............................gud luck
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