A community for students.
Here's the question you clicked on:
 0 viewing
zucchini
 3 years ago
The top of a wheel of mass M and radius R is connected to a spring (at its equilibrium length) with spring constant k, as shown in Fig. 6.33. Assume that all the mass of the wheel is at its center. If the wheel rolls without slipping, what is the frequency of (small) oscillations? The top of a wheel of mass M and radius R is connected to a spring (at its equilibrium length) with spring constant k, as shown in Fig. 6.33. Assume that all the mass of the wheel is at its center. If the wheel rolls without slipping, what is the frequency of (small) oscillations? @MIT 8.01 Physics …
zucchini
 3 years ago
The top of a wheel of mass M and radius R is connected to a spring (at its equilibrium length) with spring constant k, as shown in Fig. 6.33. Assume that all the mass of the wheel is at its center. If the wheel rolls without slipping, what is the frequency of (small) oscillations? The top of a wheel of mass M and radius R is connected to a spring (at its equilibrium length) with spring constant k, as shown in Fig. 6.33. Assume that all the mass of the wheel is at its center. If the wheel rolls without slipping, what is the frequency of (small) oscillations? @MIT 8.01 Physics …

This Question is Closed

arijit.mech
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1320493173057:dw actually moi about the instantaneous center of the wheel is given by 0.5mr^2+m(2r)^2 =4.5mr^2 now d/dt(KE+PE+RE)=0 KE=kinetic energy=.5mv^2 PE=potential energy=.5KX^2 RE=ROTATIONAL ENERGY=.5IW^2

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Although this is 5 months old, it's still worth it correcting the few mistakes in the answer. KE : correct RE : zero because the problem states that we have a pointmass at the centre of the wheel. PE : the displacement of the end of the spring is twice that of the centre (no slipping) => PE = 1/2k(2x)²
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.