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King
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Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D.
What is the probability that BD>5*sqrt(2) Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D.
What is the probability that BD>5*sqrt(2) @Mathematics
 3 years ago
 3 years ago
King Group Title
Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D. What is the probability that BD>5*sqrt(2) Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D. What is the probability that BD>5*sqrt(2) @Mathematics
 3 years ago
 3 years ago

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King Group TitleBest ResponseYou've already chosen the best response.0
dw:1320476146215:dw
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
the answer must be 1/sqrt(3)
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
answer dw:1320476924776:dw
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
how did u take as 15 and 45?
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
i never said that CBD is a right isosceles triangle
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
since we want hat BD> 5sqrt(2)........(I) we know that....10/sine(BDA) = BD/ sine(DAB) since.... sine(DAB) = 1/2 therefore..... BD = 5/ sine(BDA) put in equation no....(I) we get..... 5/sine(BDA)> 5*sqrt(2) yaha tak smjh me aa gaya kya sb kuch????
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
so we get............ sin (BAD)<1/sqrt(2) or 180degre< BAD<135degree got it or not????
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
From here i understood how to solve Thankx very very much fr ure help.......
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
now do u understand the figure that i have made....its the boundary line of the probability...that means in that figure if we move d to the right then we will get the desired probability....... understood????
 3 years ago

King Group TitleBest ResponseYou've already chosen the best response.0
And onee day hopefully like u i will be an IITIAN Yeah i understood THANX A LOT.......
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
listen tio the important fact........ur answer would be now....... area of triangle(CBD)/ area oof the triangle (DBA) this is the main thing....
 3 years ago

shubham_khandelwal Group TitleBest ResponseYou've already chosen the best response.1
bye.....i'm leaving now...mujhe khana khane jana h aur bhi kuch kam h....i'll be back in two hrs now...do send me a request on facebook.......
 3 years ago
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