Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D.
What is the probability that BD>5*sqrt(2) Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D.
What is the probability that BD>5*sqrt(2) @Mathematics
 2 years ago
 2 years ago
Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D. What is the probability that BD>5*sqrt(2) Help.............Triangle ABC is a right triangle with angle ACB as the right angle. Angle ABC =60 degrees and AB=10. Let P be randomly chosen inside triangle ABC and extend BP to meet AC at D. What is the probability that BD>5*sqrt(2) @Mathematics
 2 years ago
 2 years ago

This Question is Closed

shubham_khandelwalBest ResponseYou've already chosen the best response.1
the answer must be 1/sqrt(3)
 2 years ago

shubham_khandelwalBest ResponseYou've already chosen the best response.1
answer dw:1320476924776:dw
 2 years ago

KingBest ResponseYou've already chosen the best response.0
how did u take as 15 and 45?
 2 years ago

KingBest ResponseYou've already chosen the best response.0
i never said that CBD is a right isosceles triangle
 2 years ago

shubham_khandelwalBest ResponseYou've already chosen the best response.1
since we want hat BD> 5sqrt(2)........(I) we know that....10/sine(BDA) = BD/ sine(DAB) since.... sine(DAB) = 1/2 therefore..... BD = 5/ sine(BDA) put in equation no....(I) we get..... 5/sine(BDA)> 5*sqrt(2) yaha tak smjh me aa gaya kya sb kuch????
 2 years ago

shubham_khandelwalBest ResponseYou've already chosen the best response.1
so we get............ sin (BAD)<1/sqrt(2) or 180degre< BAD<135degree got it or not????
 2 years ago

KingBest ResponseYou've already chosen the best response.0
From here i understood how to solve Thankx very very much fr ure help.......
 2 years ago

shubham_khandelwalBest ResponseYou've already chosen the best response.1
now do u understand the figure that i have made....its the boundary line of the probability...that means in that figure if we move d to the right then we will get the desired probability....... understood????
 2 years ago

KingBest ResponseYou've already chosen the best response.0
And onee day hopefully like u i will be an IITIAN Yeah i understood THANX A LOT.......
 2 years ago

shubham_khandelwalBest ResponseYou've already chosen the best response.1
listen tio the important fact........ur answer would be now....... area of triangle(CBD)/ area oof the triangle (DBA) this is the main thing....
 2 years ago

shubham_khandelwalBest ResponseYou've already chosen the best response.1
bye.....i'm leaving now...mujhe khana khane jana h aur bhi kuch kam h....i'll be back in two hrs now...do send me a request on facebook.......
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.