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- anonymous

Could someone help explain to me how to do this problem?

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- anonymous

Could someone help explain to me how to do this problem?

- katieb

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- anonymous

- anonymous

nyan cat cant solve math problems

- hoblos

here u must find the center of the circumscribed circle of the triangle(g1g2g3)
here the triangle seems to be right
so it is the midpoint of the hypotenuses

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- anonymous

no guaranterr that all 3 would fall on same circle so prob has n solution

- hoblos

arjuna each triangle has a circumscribed circle

- anonymous

use the orthocenter

- anonymous

interesting way to disguise math in a question ;)

- anonymous

i mean, this is an interesting application of geometry

- hoblos

sorry sarah but the orthocenter is useless here

- anonymous

its a seriously good question,
some real world problems are hokey, this one is god

- anonymous

hoblos, ok what does the orthocenter tell you ?

- anonymous

ok that makes sense, the circumcenter is the same distance to each of the three vertices, since they are radii

- hoblos

the intersection of the altitudes of the triangle

- hoblos

yup thats it

- hoblos

btw where are you from sarah?
if you dont mind

- anonymous

the orthocenter is the intersection of the perpindicular bisectors

- anonymous

i am from maryland

- hoblos

i've never heard about this :S

- hoblos

btw it is not intersection of the perpindicular bisectors it is intersection of the altitudes or heights

- anonymous

centroid?

- hoblos

what about the centroid arjuna??

- anonymous

dropping altitudes and calculating intersection

- hoblos

no centroid is dropping the medians and calculating intersection

- anonymous

Thank you, everyone! c:

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