anonymous
  • anonymous
Does this infinite series converge or diverge absolutely or conditionally? n=1 to infinity (Sin((npi/2))/n^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
sin(npi/2) oscillates between 1 and -1, but the denominator (n^3) is getting bigger as n increases. So, as the top makes the curve oscillate, the bottom is making the oscillations smaller in amplitude thus making it converge.

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