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Does this infinite series converge or diverge absolutely or conditionally?
n=1 to infinity (Sin((npi/2))/n^3
 2 years ago
 2 years ago
Does this infinite series converge or diverge absolutely or conditionally? n=1 to infinity (Sin((npi/2))/n^3
 2 years ago
 2 years ago

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sin(npi/2) oscillates between 1 and 1, but the denominator (n^3) is getting bigger as n increases. So, as the top makes the curve oscillate, the bottom is making the oscillations smaller in amplitude thus making it converge.
 2 years ago
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