pablobegins
This one's a challenging one...
Delete
Share
This Question is Closed
pablobegins
Best Response
You've already chosen the best response.
1
amistre64
Best Response
You've already chosen the best response.
0
r=radius, and a =angle
height of a hole (y) is simply: r sin(a)
and the x part is: r cos(a)
pablobegins
Best Response
You've already chosen the best response.
1
y1 or y2? can this be applied for both?
amistre64
Best Response
You've already chosen the best response.
0
this is applied to any hole that you need to find.
r = 42 in this case from what I can tell, and you just have to keep an eye on your angles for the "a"
amistre64
Best Response
You've already chosen the best response.
0
r = 46 that is ;)
pablobegins
Best Response
You've already chosen the best response.
1
so for x1, y1, for example, the angle is 36, correct? (just trying to make sure i'm understanding)
jamalahmed2068
Best Response
You've already chosen the best response.
1
y1=46sin(27)
amistre64
Best Response
You've already chosen the best response.
0
nah x1,y1 has an angle of 27
amistre64
Best Response
You've already chosen the best response.
0
x2,y2 is 27+27 = 54
jamalahmed2068
Best Response
You've already chosen the best response.
1
y2=46cos(36)
amistre64
Best Response
You've already chosen the best response.
0
it less confusing if you measure your ys in sins but you could do y2 that way as well
pablobegins
Best Response
You've already chosen the best response.
1
how do i find x?
amistre64
Best Response
You've already chosen the best response.
0
x = r cos(a)
pablobegins
Best Response
You've already chosen the best response.
1
52 cos (27)?
jamalahmed2068
Best Response
You've already chosen the best response.
1
x1=46cos(27)
x2=46sin(36)
amistre64
Best Response
You've already chosen the best response.
0
no, the hole hasnt moved from its original spot; the radius is still 46
amistre64
Best Response
You've already chosen the best response.
0
ignore the stuff they put in there to distract you with
jamalahmed2068
Best Response
You've already chosen the best response.
1
Is it really challenging????
amistre64
Best Response
You've already chosen the best response.
0
it can be
pablobegins
Best Response
You've already chosen the best response.
1
i'm sorry, im just terrible at math >-<
pablobegins
Best Response
You've already chosen the best response.
1
how do i give you both the points?
amistre64
Best Response
You've already chosen the best response.
0
each name has a good answer option beside it if you like
pablobegins
Best Response
You've already chosen the best response.
1
got it, thank you :D