• anonymous
I have this systems of equation and I'm suppose to solve it using substitution. 2a-b=17 3a+4b=-13 I have the first part of the answer: a=(81/5). Then, I plug it into the other equation: 2a-b=17, which becomes 2(81/5)-b=17. So, I get (162/5)-b=17. This is the part where I'm completely lost. Do I subtract (162/5) from both sides, or do I multiply both sides by 5 and then subtract 162?
  • schrodinger
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  • anonymous
you just need to move (162/5) from left to the right so, become -b=17-(162/5) and then -b= -(77/5) so, b will be 77/5. and done

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