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Achelous
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I have this systems of equation and I'm suppose to solve it using substitution.
2ab=17
3a+4b=13
I have the first part of the answer: a=(81/5). Then, I plug it into the other equation: 2ab=17, which becomes 2(81/5)b=17.
So, I get (162/5)b=17. This is the part where I'm completely lost. Do I subtract (162/5) from both sides, or do I multiply both sides by 5 and then subtract 162?
 2 years ago
 2 years ago
Achelous Group Title
I have this systems of equation and I'm suppose to solve it using substitution. 2ab=17 3a+4b=13 I have the first part of the answer: a=(81/5). Then, I plug it into the other equation: 2ab=17, which becomes 2(81/5)b=17. So, I get (162/5)b=17. This is the part where I'm completely lost. Do I subtract (162/5) from both sides, or do I multiply both sides by 5 and then subtract 162?
 2 years ago
 2 years ago

This Question is Closed

dinainjune Group TitleBest ResponseYou've already chosen the best response.1
you just need to move (162/5) from left to the right so, become b=17(162/5) and then b= (77/5) so, b will be 77/5. and done
 2 years ago
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