differentiate. [ln(x)]/[1+ln(2x)] please show steps

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differentiate. [ln(x)]/[1+ln(2x)] please show steps

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Quotient rule says d/dx(f(x)/g(x)) = (f'(x)g(x)-g'(x)f(x))/(g(x))^2 Or more simply, (the derivative of the top times the bottom) minus (the derivative of the bottom times the top) all over the bottom squared. (1/x) = derivative of ln(x) (1/x)(1+ln2x)-(1/2x)(lnx) --------------------- (1+ln2x)^2
i dont use chain rule on the bottom?
The bottom is just squared, you don't take the derivative of the bottom.

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oh, right. isnt the derivative of 1+ln2x = 2/2x?
Yeah, you're right the derivative of ln(2x) is 2/2x due to the chain rule, whoops.
alrite cool. thamks dude.

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