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mr.luna

differentiate. [ln(x)]/[1+ln(2x)] please show steps

  • 2 years ago
  • 2 years ago

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  1. Kainui
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    Quotient rule says d/dx(f(x)/g(x)) = (f'(x)g(x)-g'(x)f(x))/(g(x))^2 Or more simply, (the derivative of the top times the bottom) minus (the derivative of the bottom times the top) all over the bottom squared. (1/x) = derivative of ln(x) (1/x)(1+ln2x)-(1/2x)(lnx) --------------------- (1+ln2x)^2

    • 2 years ago
  2. mr.luna
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    i dont use chain rule on the bottom?

    • 2 years ago
  3. Kainui
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    The bottom is just squared, you don't take the derivative of the bottom.

    • 2 years ago
  4. mr.luna
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    oh, right. isnt the derivative of 1+ln2x = 2/2x?

    • 2 years ago
  5. Kainui
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    Yeah, you're right the derivative of ln(2x) is 2/2x due to the chain rule, whoops.

    • 2 years ago
  6. mr.luna
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    alrite cool. thamks dude.

    • 2 years ago
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