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anonymous
 4 years ago
differentiate. [ln(x)]/[1+ln(2x)] please show steps
anonymous
 4 years ago
differentiate. [ln(x)]/[1+ln(2x)] please show steps

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Kainui
 4 years ago
Best ResponseYou've already chosen the best response.1Quotient rule says d/dx(f(x)/g(x)) = (f'(x)g(x)g'(x)f(x))/(g(x))^2 Or more simply, (the derivative of the top times the bottom) minus (the derivative of the bottom times the top) all over the bottom squared. (1/x) = derivative of ln(x) (1/x)(1+ln2x)(1/2x)(lnx)  (1+ln2x)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont use chain rule on the bottom?

Kainui
 4 years ago
Best ResponseYou've already chosen the best response.1The bottom is just squared, you don't take the derivative of the bottom.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh, right. isnt the derivative of 1+ln2x = 2/2x?

Kainui
 4 years ago
Best ResponseYou've already chosen the best response.1Yeah, you're right the derivative of ln(2x) is 2/2x due to the chain rule, whoops.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alrite cool. thamks dude.
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