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mr.luna
 4 years ago
differentiate. [(ae^x)+b]/[(ce^x)+d]... a,b,c,d are constants. i got this far..
mr.luna
 4 years ago
differentiate. [(ae^x)+b]/[(ce^x)+d]... a,b,c,d are constants. i got this far..

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mr.luna
 4 years ago
Best ResponseYou've already chosen the best response.0\[[(ae^x+b)(ce^x+e^x)(ce^x+d)(ae^x+e^x)]/[(ce^x+d)^2]\]

mr.luna
 4 years ago
Best ResponseYou've already chosen the best response.0i dont know how to get the answer which is this..

mr.luna
 4 years ago
Best ResponseYou've already chosen the best response.0\[[(adbc)e^x]/[(ce^x+d)^2]\]

Justin7771
 4 years ago
Best ResponseYou've already chosen the best response.0Do you know the quotient rule? d/(dx)[(f(x))/(g(x))]= (g(x)f^'(x)f(x)g^'(x))/([g(x)]^2). I think you should just be able to apply that It's too long to write out but this shows step by step how to do it http://www.wolframalpha.com/input/?i=%28ae^x%2Bb%29%2F%28%28ce^x%29%2Bd%29

Justin7771
 4 years ago
Best ResponseYou've already chosen the best response.0I don't think that the answer you got is right

Xavier
 4 years ago
Best ResponseYou've already chosen the best response.0How did you get the (ce^x+e^x) term?
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