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differentiate. [(ae^x)+b]/[(ce^x)+d]... a,b,c,d are constants. i got this far..
 2 years ago
 2 years ago
differentiate. [(ae^x)+b]/[(ce^x)+d]... a,b,c,d are constants. i got this far..
 2 years ago
 2 years ago

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mr.lunaBest ResponseYou've already chosen the best response.0
\[[(ae^x+b)(ce^x+e^x)(ce^x+d)(ae^x+e^x)]/[(ce^x+d)^2]\]
 2 years ago

mr.lunaBest ResponseYou've already chosen the best response.0
i dont know how to get the answer which is this..
 2 years ago

mr.lunaBest ResponseYou've already chosen the best response.0
\[[(adbc)e^x]/[(ce^x+d)^2]\]
 2 years ago

Justin7771Best ResponseYou've already chosen the best response.0
Do you know the quotient rule? d/(dx)[(f(x))/(g(x))]= (g(x)f^'(x)f(x)g^'(x))/([g(x)]^2). I think you should just be able to apply that It's too long to write out but this shows step by step how to do it http://www.wolframalpha.com/input/?i=%28ae^x%2Bb%29%2F%28%28ce^x%29%2Bd%29
 2 years ago

Justin7771Best ResponseYou've already chosen the best response.0
I don't think that the answer you got is right
 2 years ago

XavierBest ResponseYou've already chosen the best response.0
How did you get the (ce^x+e^x) term?
 2 years ago
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