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mr.luna

  • 4 years ago

differentiate. [(ae^x)+b]/[(ce^x)+d]... a,b,c,d are constants. i got this far..

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  1. mr.luna
    • 4 years ago
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    \[[(ae^x+b)(ce^x+e^x)-(ce^x+d)(ae^x+e^x)]/[(ce^x+d)^2]\]

  2. mr.luna
    • 4 years ago
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    i dont know how to get the answer which is this..

  3. mr.luna
    • 4 years ago
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    \[[(ad-bc)e^x]/[(ce^x+d)^2]\]

  4. Justin7771
    • 4 years ago
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    Do you know the quotient rule? d/(dx)[(f(x))/(g(x))]= (g(x)f^'(x)-f(x)g^'(x))/([g(x)]^2). I think you should just be able to apply that It's too long to write out but this shows step by step how to do it http://www.wolframalpha.com/input/?i=%28ae^x%2Bb%29%2F%28%28ce^x%29%2Bd%29

  5. Justin7771
    • 4 years ago
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    I don't think that the answer you got is right

  6. Xavier
    • 4 years ago
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    How did you get the (ce^x+e^x) term?

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