anonymous
  • anonymous
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
does this really say \[2^{\sin(\pi)x}\]?
anonymous
  • anonymous
\[2^{\sin(\pi x)}\] perpaps
anonymous
  • anonymous
or is it \[2^{\sin(\pi x)}\]

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anonymous
  • anonymous
flip the pi and x
anonymous
  • anonymous
if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]
anonymous
  • anonymous
oh wait . you got it right. my basd vison
anonymous
  • anonymous
ok got it. thanks
anonymous
  • anonymous
yw
anonymous
  • anonymous
hello myininaya!
myininaya
  • myininaya
satellite i need your help
anonymous
  • anonymous
i see you in chat
myininaya
  • myininaya
ok

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