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mr.luna

differentiate. 2^sin(pi)x .... im completely lost. please explain steps.

  • 2 years ago
  • 2 years ago

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  1. satellite73
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    does this really say \[2^{\sin(\pi)x}\]?

    • 2 years ago
  2. Xavier
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    \[2^{\sin(\pi x)}\] perpaps

    • 2 years ago
  3. satellite73
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    or is it \[2^{\sin(\pi x)}\]

    • 2 years ago
  4. mr.luna
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    flip the pi and x

    • 2 years ago
  5. satellite73
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    if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]

    • 2 years ago
  6. mr.luna
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    oh wait . you got it right. my basd vison

    • 2 years ago
  7. mr.luna
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    ok got it. thanks

    • 2 years ago
  8. satellite73
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    yw

    • 2 years ago
  9. satellite73
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    hello myininaya!

    • 2 years ago
  10. myininaya
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    satellite i need your help

    • 2 years ago
  11. satellite73
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    i see you in chat

    • 2 years ago
  12. myininaya
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    ok

    • 2 years ago
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