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differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
 2 years ago
 2 years ago
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
 2 years ago
 2 years ago

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satellite73Best ResponseYou've already chosen the best response.1
does this really say \[2^{\sin(\pi)x}\]?
 2 years ago

XavierBest ResponseYou've already chosen the best response.0
\[2^{\sin(\pi x)}\] perpaps
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
or is it \[2^{\sin(\pi x)}\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]
 2 years ago

mr.lunaBest ResponseYou've already chosen the best response.0
oh wait . you got it right. my basd vison
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
satellite i need your help
 2 years ago
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