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mr.luna

  • 4 years ago

differentiate. 2^sin(pi)x .... im completely lost. please explain steps.

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  1. anonymous
    • 4 years ago
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    does this really say \[2^{\sin(\pi)x}\]?

  2. Xavier
    • 4 years ago
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    \[2^{\sin(\pi x)}\] perpaps

  3. anonymous
    • 4 years ago
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    or is it \[2^{\sin(\pi x)}\]

  4. mr.luna
    • 4 years ago
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    flip the pi and x

  5. anonymous
    • 4 years ago
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    if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]

  6. mr.luna
    • 4 years ago
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    oh wait . you got it right. my basd vison

  7. mr.luna
    • 4 years ago
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    ok got it. thanks

  8. anonymous
    • 4 years ago
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    yw

  9. anonymous
    • 4 years ago
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    hello myininaya!

  10. myininaya
    • 4 years ago
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    satellite i need your help

  11. anonymous
    • 4 years ago
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    i see you in chat

  12. myininaya
    • 4 years ago
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    ok

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