A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 4 years ago
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
anonymous
 4 years ago
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does this really say \[2^{\sin(\pi)x}\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[2^{\sin(\pi x)}\] perpaps

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or is it \[2^{\sin(\pi x)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh wait . you got it right. my basd vison

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0satellite i need your help
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.