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mr.luna
 3 years ago
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
mr.luna
 3 years ago
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1does this really say \[2^{\sin(\pi)x}\]?

Xavier
 3 years ago
Best ResponseYou've already chosen the best response.0\[2^{\sin(\pi x)}\] perpaps

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1or is it \[2^{\sin(\pi x)}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1if it is the second one, recall that \[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule \[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]

mr.luna
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait . you got it right. my basd vison

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.0satellite i need your help
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