mr.luna
differentiate. 2^sin(pi)x .... im completely lost. please explain steps.
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anonymous
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does this really say
\[2^{\sin(\pi)x}\]?
Xavier
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\[2^{\sin(\pi x)}\] perpaps
anonymous
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or is it
\[2^{\sin(\pi x)}\]
mr.luna
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flip the pi and x
anonymous
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if it is the second one, recall that
\[\frac{d}{dx}2^x=2^x\ln(2)\] so by the chain rule
\[\frac{d}{dx}2^{\sin(\pi x)}=2^{\sin(\pi x)}\times \ln(2)\times \cos(\pi x)\times \pi\]
mr.luna
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oh wait . you got it right. my basd vison
mr.luna
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ok got it. thanks
anonymous
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yw
anonymous
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hello myininaya!
myininaya
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satellite i need your help
anonymous
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i see you in chat
myininaya
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ok