anonymous
  • anonymous
is this double chain rule? e^(xsin2x)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
yes
anonymous
  • anonymous
double chain rule with a product rule
anonymous
  • anonymous
which rule do i use? a^x'=a^xlna or e^u=e^udu/dx

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anonymous
  • anonymous
e^u=e^udu/dx
anonymous
  • anonymous
[ e^u ] du u = xsin2x
anonymous
  • anonymous
i get for du/dx x*cos2x*2+sin2x
anonymous
  • anonymous
is that right?
anonymous
  • anonymous
yup
anonymous
  • anonymous
cool beans

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