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mr.luna

  • 4 years ago

is this double chain rule? e^(xsin2x)

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  1. MathMind
    • 4 years ago
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    yes

  2. MathMind
    • 4 years ago
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    double chain rule with a product rule

  3. mr.luna
    • 4 years ago
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    which rule do i use? a^x'=a^xlna or e^u=e^udu/dx

  4. MathMind
    • 4 years ago
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    e^u=e^udu/dx

  5. MathMind
    • 4 years ago
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    [ e^u ] du u = xsin2x

  6. mr.luna
    • 4 years ago
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    i get for du/dx x*cos2x*2+sin2x

  7. mr.luna
    • 4 years ago
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    is that right?

  8. MathMind
    • 4 years ago
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    yup

  9. mr.luna
    • 4 years ago
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    cool beans

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