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anonymous
 4 years ago
is this double chain rule? e^(xsin2x)
anonymous
 4 years ago
is this double chain rule? e^(xsin2x)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0double chain rule with a product rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which rule do i use? a^x'=a^xlna or e^u=e^udu/dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0[ e^u ] du u = xsin2x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i get for du/dx x*cos2x*2+sin2x
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