At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

so P(0)=100 P(3)=420

i set the equation P(3)=100e^3k=420 i solved and got k=ln42/3

is a [100e^[(ln42/3)(t)]

b) i just plug in 3 for t to the equation in a) ?

for d) i put equation a) equal to 10,000 right?

im stuck on c) though. how do you do that?

i got it down to 100(42^t/3) i dont how to dervie?

I think your initial conditions are wrong. You wrote P(3) = 420, and on the problem says P(1) = 420

\[420 = 100e^{k(1)}\]

so, \[k = \ln4.2\]

ok crap .yeah your right! good catch

\[P = 100e^{\ln(4.2)t}\]

if you derive you get: \[\frac{d}{dt}100e^{(\ln 4.2)k}= 100(\ln4.2)e^{(\ln 4.2)k}\]

sorry its t instead of k

im trying to get waht you got for the derviative right now. its not coming out for me.

what did you get?

instead of ln4.2 i get 4.2k

remember that \[\frac{d}{dx}e^{ax} = ae^x\]

Sorry i missed an "a"
\[\frac{d}{dx}e^{ax}=ae^{ax}\]

oh. ok. got it now. thanks

You're welcome.