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mr.luna

  • 4 years ago

im stuck here, please solve for t.

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  1. MathMind
    • 4 years ago
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    t = 1.45126

  2. mr.luna
    • 4 years ago
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    \[(10/11)=(75/110)^(t/30)\]

  3. mr.luna
    • 4 years ago
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    how did you get that math mind? i hadnt even posted the equation

  4. myininaya
    • 4 years ago
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    it looks like you raised one of your parenthesis does that mean t/30) should also be raised?

  5. mr.luna
    • 4 years ago
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    oops. im retyping.yes myininaya

  6. karatechopper
    • 4 years ago
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    t=440

  7. mr.luna
    • 4 years ago
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    \[(10/11)=(75/110)^(t/30)\]

  8. mr.luna
    • 4 years ago
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    what the heck it doesnt do it.

  9. MathMind
    • 4 years ago
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    lmfao, thanks for the medal.... you gotta type into { }

  10. myininaya
    • 4 years ago
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    \[\frac{10}{11}=(\frac{75}{110})^{\frac{t}{30}}\] take natural log of both sides so then we can write \[\ln(\frac{10}{11})=\frac{t}{30} \ln(\frac{75}{110})\]

  11. mr.luna
    • 4 years ago
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    im gona check your answer karate

  12. mr.luna
    • 4 years ago
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    doesnt there have to be an e to bring down the t/30

  13. karatechopper
    • 4 years ago
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    k i just tried it i didnt really understand what myin was saying about raised so i may have it wrong

  14. mr.luna
    • 4 years ago
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    yup karate. your wrong.

  15. myininaya
    • 4 years ago
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    remember: \[\ln(x^r)=r \ln(x)\] \[30 \cdot \ln(\frac{10}{11}) \cdot \frac{1}{\ln(\frac{75}{110})}=t\]

  16. karatechopper
    • 4 years ago
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    i thought so.... wtheck myin???? what math level is this?!?!?!?!

  17. mr.luna
    • 4 years ago
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    ok myiniaya im working on getting your resulsts with your intial setup

  18. myininaya
    • 4 years ago
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    t is approx=7.465700356

  19. mr.luna
    • 4 years ago
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    i get 30 times( ln10/11over ln75/110)

  20. mr.luna
    • 4 years ago
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    i dont have a calculator

  21. myininaya
    • 4 years ago
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    samething

  22. mr.luna
    • 4 years ago
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    alrie thanks

  23. mr.luna
    • 4 years ago
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    do you what a medal?

  24. myininaya
    • 4 years ago
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    \[30 \cdot \ln(\frac{10}{11}) \cdot \frac{1}{\ln(\frac{75}{110})}= 30 \cdot \frac{\ln(\frac{10}{11})}{\ln(\frac{75}{110})}\]

  25. myininaya
    • 4 years ago
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    you can also write this a couple of other different ways

  26. mr.luna
    • 4 years ago
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    yup i got that. :)

  27. mr.luna
    • 4 years ago
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    your awsome dude god bless

  28. myininaya
    • 4 years ago
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    using our properties of log

  29. myininaya
    • 4 years ago
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    i prefer to be called a dudette thanks

  30. karatechopper
    • 4 years ago
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    lol myin and i r girls!

  31. mr.luna
    • 4 years ago
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    thanks sista form anotha mista. :)

  32. myininaya
    • 4 years ago
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    thats goofy but i accept lol

  33. mr.luna
    • 4 years ago
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    coo

  34. karatechopper
    • 4 years ago
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    hahahahahahahahahahaha! but i come from a mother not a father. i dont think males get pregnant....hmmmjk!

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