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Outkast3r09

  • 3 years ago

Find absolute extrema of f(x,y)= x^2+2xy+y^2, bound by |x|<=2, |y|<=1 Find absolute extrema of f(x,y)= x^2+2xy+y^2, bound by |x|<=2, |y|<=1 @Mathematics

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  1. Outkast3r09
    • 3 years ago
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    now i got the maximum by putting my lines x=-2,2 and y=-1,1 however when i try to find the functions zeroes i get x=-y... am i supposed to put that into the equation and evaluate so.... x^2+2(-y)y+y^2=x^2?

  2. Outkast3r09
    • 3 years ago
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    and they get (x,-x,0) as an absolute minima

  3. Outkast3r09
    • 3 years ago
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    just wondering if i did right in which the function x^2 will always be positive... and what would happen if i got something that didn't exactly get 0?

  4. FreeTrader
    • 3 years ago
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    Is this Calculus 2? I am doing single variable versions of this in Calculus 1 this week, too.

  5. Outkast3r09
    • 3 years ago
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    this is calculus 3... calculus two is more into surface area and integrals... calc 3 is multivariable

  6. FreeTrader
    • 3 years ago
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    Right on. Bye the way, I thought you did great work helping that fellow rationalize the denom. Good teaching!

  7. Outkast3r09
    • 3 years ago
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    thanks

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