A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Find absolute extrema of f(x,y)= x^2+2xy+y^2, bound by x<=2, y<=1 Find absolute extrema of f(x,y)= x^2+2xy+y^2, bound by x<=2, y<=1 @Mathematics
anonymous
 5 years ago
Find absolute extrema of f(x,y)= x^2+2xy+y^2, bound by x<=2, y<=1 Find absolute extrema of f(x,y)= x^2+2xy+y^2, bound by x<=2, y<=1 @Mathematics

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i got the maximum by putting my lines x=2,2 and y=1,1 however when i try to find the functions zeroes i get x=y... am i supposed to put that into the equation and evaluate so.... x^2+2(y)y+y^2=x^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and they get (x,x,0) as an absolute minima

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just wondering if i did right in which the function x^2 will always be positive... and what would happen if i got something that didn't exactly get 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this Calculus 2? I am doing single variable versions of this in Calculus 1 this week, too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is calculus 3... calculus two is more into surface area and integrals... calc 3 is multivariable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right on. Bye the way, I thought you did great work helping that fellow rationalize the denom. Good teaching!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.