## MightySmurf 4 years ago In the scene in an action movie, a stuntman jumps from the top of one building to the top of another building 4.0 m away. After a running start, he leaps at an angle of 15 degrees with respect to the flat roof while traveling at a speed of 5.0 m/s. Will he make it to the other roof, which is 2.5 m shorter than the building he jumps from.

1. umichzane13

gimme one second and ill help you, im working it out now

2. MightySmurf

kk thanks

3. umichzane13

Yes he makes it to the other roof. Do you want me to just explain how I got there?

4. MightySmurf

if u dnt mind

5. umichzane13

Ok, well first you need to break the initial velocity into components, The x component will be used to find the total horizontal distance traveled (to see if he makes the other roof) and the y component of the velocity will be used to find the total time the person is in the air.

6. MightySmurf

ok

7. umichzane13

So, use \[\Delta y = 1/2*a*\Delta t^2 + V_iy*\Delta t \] where a is -(.81 m/s^2 and delta y is -1.5 m and Viy is 5*sin(15). Solve for t. Then use \[x = V_x*\Delta t\] where Vx=5*cos(15) and x is the total distance traveled. This gives 4.7147 m, so he makes it to the other ledge

8. MightySmurf

omg wow that looks confusing

9. umichzane13

nah its easy lol, i hope i didnt make it complicated... I dont normally do physics with algebra

10. MightySmurf

how old r u

11. umichzane13

20, in college for Engineering

12. MightySmurf

o ok thats cool i wanna be a mechanic

13. umichzane13

Nice! well good luck with physics and math, I am an engineer but its still difficult!

14. MightySmurf

thank you and thanks for the help to