In the scene in an action movie, a stuntman jumps from the top of one building to the top of another building 4.0 m away. After a running start, he leaps at an angle of 15 degrees with respect to the flat roof while traveling at a speed of 5.0 m/s. Will he make it to the other roof, which is 2.5 m shorter than the building he jumps from.

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In the scene in an action movie, a stuntman jumps from the top of one building to the top of another building 4.0 m away. After a running start, he leaps at an angle of 15 degrees with respect to the flat roof while traveling at a speed of 5.0 m/s. Will he make it to the other roof, which is 2.5 m shorter than the building he jumps from.

Physics
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gimme one second and ill help you, im working it out now
kk thanks
Yes he makes it to the other roof. Do you want me to just explain how I got there?

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Other answers:

if u dnt mind
Ok, well first you need to break the initial velocity into components, The x component will be used to find the total horizontal distance traveled (to see if he makes the other roof) and the y component of the velocity will be used to find the total time the person is in the air.
ok
So, use \[\Delta y = 1/2*a*\Delta t^2 + V_iy*\Delta t \] where a is -(.81 m/s^2 and delta y is -1.5 m and Viy is 5*sin(15). Solve for t. Then use \[x = V_x*\Delta t\] where Vx=5*cos(15) and x is the total distance traveled. This gives 4.7147 m, so he makes it to the other ledge
omg wow that looks confusing
nah its easy lol, i hope i didnt make it complicated... I dont normally do physics with algebra
how old r u
20, in college for Engineering
o ok thats cool i wanna be a mechanic
Nice! well good luck with physics and math, I am an engineer but its still difficult!
thank you and thanks for the help to

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