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MightySmurf
In the scene in an action movie, a stuntman jumps from the top of one building to the top of another building 4.0 m away. After a running start, he leaps at an angle of 15 degrees with respect to the flat roof while traveling at a speed of 5.0 m/s. Will he make it to the other roof, which is 2.5 m shorter than the building he jumps from.
gimme one second and ill help you, im working it out now
Yes he makes it to the other roof. Do you want me to just explain how I got there?
Ok, well first you need to break the initial velocity into components, The x component will be used to find the total horizontal distance traveled (to see if he makes the other roof) and the y component of the velocity will be used to find the total time the person is in the air.
So, use \[\Delta y = 1/2*a*\Delta t^2 + V_iy*\Delta t \] where a is -(.81 m/s^2 and delta y is -1.5 m and Viy is 5*sin(15). Solve for t. Then use \[x = V_x*\Delta t\] where Vx=5*cos(15) and x is the total distance traveled. This gives 4.7147 m, so he makes it to the other ledge
omg wow that looks confusing
nah its easy lol, i hope i didnt make it complicated... I dont normally do physics with algebra
20, in college for Engineering
o ok thats cool i wanna be a mechanic
Nice! well good luck with physics and math, I am an engineer but its still difficult!
thank you and thanks for the help to