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MightySmurf

  • 3 years ago

In the scene in an action movie, a stuntman jumps from the top of one building to the top of another building 4.0 m away. After a running start, he leaps at an angle of 15 degrees with respect to the flat roof while traveling at a speed of 5.0 m/s. Will he make it to the other roof, which is 2.5 m shorter than the building he jumps from.

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  1. umichzane13
    • 3 years ago
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    gimme one second and ill help you, im working it out now

  2. MightySmurf
    • 3 years ago
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    kk thanks

  3. umichzane13
    • 3 years ago
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    Yes he makes it to the other roof. Do you want me to just explain how I got there?

  4. MightySmurf
    • 3 years ago
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    if u dnt mind

  5. umichzane13
    • 3 years ago
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    Ok, well first you need to break the initial velocity into components, The x component will be used to find the total horizontal distance traveled (to see if he makes the other roof) and the y component of the velocity will be used to find the total time the person is in the air.

  6. MightySmurf
    • 3 years ago
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    ok

  7. umichzane13
    • 3 years ago
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    So, use \[\Delta y = 1/2*a*\Delta t^2 + V_iy*\Delta t \] where a is -(.81 m/s^2 and delta y is -1.5 m and Viy is 5*sin(15). Solve for t. Then use \[x = V_x*\Delta t\] where Vx=5*cos(15) and x is the total distance traveled. This gives 4.7147 m, so he makes it to the other ledge

  8. MightySmurf
    • 3 years ago
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    omg wow that looks confusing

  9. umichzane13
    • 3 years ago
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    nah its easy lol, i hope i didnt make it complicated... I dont normally do physics with algebra

  10. MightySmurf
    • 3 years ago
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    how old r u

  11. umichzane13
    • 3 years ago
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    20, in college for Engineering

  12. MightySmurf
    • 3 years ago
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    o ok thats cool i wanna be a mechanic

  13. umichzane13
    • 3 years ago
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    Nice! well good luck with physics and math, I am an engineer but its still difficult!

  14. MightySmurf
    • 3 years ago
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    thank you and thanks for the help to

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