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 3 years ago
Simplify and show work please!
^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2
Thanks Simplify and show work please!
^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2
Thanks @Mathematics
 3 years ago
Simplify and show work please! ^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2 Thanks Simplify and show work please! ^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2 Thanks @Mathematics

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fr33
 3 years ago
Best ResponseYou've already chosen the best response.0Can you please explain your notation?

greeneyes<3
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[3]{4x^3y^5}\times \sqrt[3]{12y^2}\]

greeneyes<3
 3 years ago
Best ResponseYou've already chosen the best response.1idk if this steps are right. ^3sqrt. x^3y^3 times ^3sqrt. 4y^2 times ^3 sqrt. 12y^2

fr33
 3 years ago
Best ResponseYou've already chosen the best response.0since you have to isolate for x or y, you decide which first and use the one you didnt isolate inside of the equation to later evaluate. Since you wrote all that, I dont quite get the steps you did....

greeneyes<3
 3 years ago
Best ResponseYou've already chosen the best response.1okay. I hope the server is back.\[\sqrt[3]{x^3y^3y^3}\times \sqrt[3]{4y}\times \sqrt[3]{12}\]

greeneyes<3
 3 years ago
Best ResponseYou've already chosen the best response.1I know the answer is\[2xy^2\sqrt[3]{6y}\] but how do you get that?

fr33
 3 years ago
Best ResponseYou've already chosen the best response.0How did you do it and do not know how you got there? lol

greeneyes<3
 3 years ago
Best ResponseYou've already chosen the best response.1I separated all the ^3 from the numbers/variables that couldnt be ^3. So\[\sqrt[3]{x^3y^3y^3}\] are separated from\[\sqrt[3]{4y} \times \sqrt[3]{12}\] and so from that info the answer is :\[2xy^2\sqrt[3]{6y}\] does it make sense or no?
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