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greeneyes<3

  • 4 years ago

Simplify and show work please! ^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2 Thanks Simplify and show work please! ^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2 Thanks @Mathematics

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  1. fr33
    • 4 years ago
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    Can you please explain your notation?

  2. greeneyes<3
    • 4 years ago
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    \[\sqrt[3]{4x^3y^5}\times \sqrt[3]{12y^2}\]

  3. greeneyes<3
    • 4 years ago
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    Yayyy! [:

  4. greeneyes<3
    • 4 years ago
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    idk if this steps are right. ^3sqrt. x^3y^3 times ^3sqrt. 4y^2 times ^3 sqrt. 12y^2

  5. fr33
    • 4 years ago
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    since you have to isolate for x or y, you decide which first and use the one you didnt isolate inside of the equation to later evaluate. Since you wrote all that, I dont quite get the steps you did....

  6. greeneyes<3
    • 4 years ago
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    okay. I hope the server is back.\[\sqrt[3]{x^3y^3y^3}\times \sqrt[3]{4y}\times \sqrt[3]{12}\]

  7. greeneyes<3
    • 4 years ago
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    I know the answer is\[2xy^2\sqrt[3]{6y}\] but how do you get that?

  8. fr33
    • 4 years ago
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    How did you do it and do not know how you got there? lol

  9. greeneyes<3
    • 4 years ago
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    I separated all the ^3 from the numbers/variables that couldnt be ^3. So\[\sqrt[3]{x^3y^3y^3}\] are separated from\[\sqrt[3]{4y} \times \sqrt[3]{12}\] and so from that info the answer is :\[2xy^2\sqrt[3]{6y}\] does it make sense or no?

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