## A community for students. Sign up today

Here's the question you clicked on:

## anonymous 4 years ago Simplify and show work please! ^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2 Thanks Simplify and show work please! ^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2 Thanks @Mathematics

• This Question is Closed
1. anonymous

Can you please explain your notation?

2. anonymous

$\sqrt[3]{4x^3y^5}\times \sqrt[3]{12y^2}$

3. anonymous

Yayyy! [:

4. anonymous

idk if this steps are right. ^3sqrt. x^3y^3 times ^3sqrt. 4y^2 times ^3 sqrt. 12y^2

5. anonymous

since you have to isolate for x or y, you decide which first and use the one you didnt isolate inside of the equation to later evaluate. Since you wrote all that, I dont quite get the steps you did....

6. anonymous

okay. I hope the server is back.$\sqrt[3]{x^3y^3y^3}\times \sqrt[3]{4y}\times \sqrt[3]{12}$

7. anonymous

I know the answer is$2xy^2\sqrt[3]{6y}$ but how do you get that?

8. anonymous

How did you do it and do not know how you got there? lol

9. anonymous

I separated all the ^3 from the numbers/variables that couldnt be ^3. So$\sqrt[3]{x^3y^3y^3}$ are separated from$\sqrt[3]{4y} \times \sqrt[3]{12}$ and so from that info the answer is :$2xy^2\sqrt[3]{6y}$ does it make sense or no?

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy