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FreeTrader

Can you help me see where I am stuck finding the zeros of this quadratic equation?

  • 2 years ago
  • 2 years ago

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  1. FreeTrader
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    \[3x^2 - 12x + 11 = 0\]

    • 2 years ago
  2. satellite73
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    quadratic formula for this one use \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=3,b=-12,c=11\]

    • 2 years ago
  3. FreeTrader
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    My student solutions manual says I should obtain \[(6 \pm \sqrt{3}) \div 3\]

    • 2 years ago
  4. satellite73
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    indeed you should

    • 2 years ago
  5. FreeTrader
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    Let's walk through this, so I can see where I am tripping over my shoelaces.

    • 2 years ago
  6. satellite73
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    first you get \[\frac{-12\pm\sqrt{(-12)^2-4\times 3\times 11}}{6}\]

    • 2 years ago
  7. FreeTrader
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    Wait a sec. I see that I made an error in the first term under the radical. I will go back to the drawing board and re-attempt this one on my own.

    • 2 years ago
  8. FreeTrader
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    By the way, how are you producing the nice looking divisor line?

    • 2 years ago
  9. satellite73
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    \frac{a}{b} looks like \[\frac{a}{b}\]

    • 2 years ago
  10. FreeTrader
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    Got it. I made simple mistakes in my substitutions, then got hung up on trying to do algebra with unduly complicated figures.

    • 2 years ago
  11. FreeTrader
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    THANKS @satellite73, you got me unstuck!

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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