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anonymous
 4 years ago
Can you please help guide me through the last steps in this equation involving logarithms?
anonymous
 4 years ago
Can you please help guide me through the last steps in this equation involving logarithms?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am solving for x. Can you nudge me about the ln properties?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.21+ln(x) = ln(4) 1 = ln(4)ln(x) 1 = ln(4/x) 4/x = e^1 4/x = e 4 = ex 4/e = x x = 4/e

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks, I'll see if I can follow this on paper here... Just a sec...

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2The properties I used were ln(x)  ln(y) = ln(x/y) and ln(x) = y converts to e^y = x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I see the division coming into play with the subtraction.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The last one is the key I was missing.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can also try \[\ln(x)=\ln(4)1\] \[x=e^{\ln(4)1}=e^{\ln(4)}\times e^{1}=\frac{4}{e}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ln x = e to what power gives us x Logarithms confuse me to no end, despite how "simple" they are supposed to be.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have duplicated the algebra, and it makes sense. Are you aware of a really good ln tutorial with exercises?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2try this page: http://www.purplemath.com/modules/solvelog.htm

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you. If you answer that tutorial question in the new Q I posted, I'd be pleased to pin a medal upon you.
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