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arjuna Group TitleBest ResponseYou've already chosen the best response.0
attachment is broken
 3 years ago

arjuna Group TitleBest ResponseYou've already chosen the best response.0
i m sorry i cant do it
 3 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
dw:1320794476045:dw It's a lousy picture, but it is trying to show that Ln (the y value of each rectangle is the y value of the curve on the left side of the rectangle) is less than the area under the curve, because the curve is "increasing continuous function". The area Rn (each rectangle takes the yvalue of the curve from its right side) is greater than A. so (1) Ln<A<Rn The picture also tries to show that each small rectangle formed by the difference in the yvalues of the Left limit and the right limit can be stacked up to produce a tall thin rectangle. It has width (ba)/n and height f(b)f(a) so (2) RnLn = (ba) ( f(b) f(a))/n from (1) we have Ln < A, or LnRn<ARn multiply both sides by 1 and flip the relation: RnLn> RnA from (2), we can substitute for RnLn to get (3) RnA < (ba) ( f(b)f(a))/n
 3 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
A nicer picture
 3 years ago
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